Need a number line to show the answer to 1/10 ÷ 2

Mathematics

1 answer:

Taya2010 [7]3 years ago

7 0

No you do not. I think I will help.

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A square pool is surrounded by a paved area that is 2 metres wide. If the area of the paving is 72m2, what is the length of the

likoan [24]

The length of the square pool is 8. 49cm

<h3>How to determine the area</h3>

Note that the formula for finding the area of a square is given as;

Area = length^2

We have

Area = 72 m²

Substitute into the formula

I^2 = 72

Find the square root of both sides

I= √72

I = 8. 49cm

The length of the square pool given as I is 8. 49cm

Thus, the length of the square pool is 8. 49cm

Learn more about area of a square here:

brainly.com/question/486778

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5 0

2 years ago

A car is traveling at a steady speed. It travels 2 1/2

Ksivusya [100]

Answer:

It will travel

$33 \frac{1}{4} \: miles$

in 45 minutes.

Step-by-step explanation:

We can solve using proportions.

$\frac{ 2\frac{1}{2} \: miles}{ 3\frac{1}{3} \: minutes} = \frac{x}{45 \: minutes} \\ \\ \frac{ 3\frac{1}{3} x}{ 3\frac{1}{3} } = \frac{ 112\frac{1}{2} }{ 3\frac{1}{3} } \\ \\ x = 33\frac{3}{4}$

6 0

3 years ago

Please help!

In-s [12.5K]

Answer: B

Explanation: an isosceles triangle has 2 sides that are the same, so if the base angles are both 34° then you can multiply that by 2 to get 68°. After that you know that you're still missing one of the angles so that missing angle is x. The equation you can set up to solve for x is the following: 68° + x° = 180°

Hope this helped! :)

8 0

2 years ago

Situation:A researcher in North America discoversa fossile that contains 65% of its originalamount of C-14..-ktN=NoeNo inital am

zheka24 [161]

SOLUTION

We have been given the equation of the decay as

$\begin{gathered} N=N_0e^{-kt} \\ where\text{ } \\ N_0=initial\text{ amount of C-14 at time t} \\ N=amount\text{ of C-14 at time t = 65\% of N}_0=0.65N_0 \\ k=0.0001 \\ t=time\text{ in years = ?} \end{gathered}$

So we are looking for the time

Plugging the values into the equation, we have