Jake has a bag of 50 beads, of which some are red and the remaining are yellow. Jake pulls out a bead from the bag, records the
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Answer: B. H(t) = -6.9(t - 2.3)² + 112
<u>Step-by-step explanation:</u>
The vertex form of a quadratic equation is: y = a(x - h)² + k
where (h, k) is the vertex ⇒ k is the maximum height
the distance traveled is when y = 0 ⇒
Given: H(t) = -7.1(t - 2.3)² + 98
maximum height (k) = 98 feet
distance traveled (x) = = 6.02 seconds
A) H(t) = -7.5(t - 2.2)² + 112
maximum height (k) = 112 feet
distance traveled (x) = = 6.06 seconds
B) H(t) = -6.9(t - 2.3)² + 112
maximum height (k) = 112 feet
distance traveled (x) = = 6.33 seconds
C) H(t) = -6.9(t - 2.4)² + 95
maximum height (k) = 95 feet
This has a lower height than the given equation.
D) H(t) = -7.5(t - 2.3)² + 95
maximum height (k) = 95 feet
This has a lower height than the given equation.
Both options A and B travel higher and stay in the air longer than last year's winner, however option B stays in the air longer than option A.
When x =170, y =10, when x = 187, y = 1, when x = 204, y = 12, when x = 221, y = 13, when x = 238, y = 14, when x = 255, y = 15, when x = 272, y = 16, when x = 289, y = 17, when x = 306, y = 18, when x = 323, y = 19, when x = 340, y = 20,
Step-by-step explanation:
Step 1; Assume y is the gallons in the tank while x is the range of the car. We need to determine the equation relating the y to the x values in the given coordinates. x is the dependent value whereas y is the independent value i.e. the value of x depends on the value of y.
Step 2; As y increases, x also increases. For every extra gallon in the tank, the car can go another 17 miles. So with y as the amount of gas in the tank in gallons and x as the range of vehicle, we get;
x = 17y, this represents the relation between x and y.
To find the gallons in the tank, y = ,
For x = 170, y = = 10,
Similarly equating the values we get that when x = 187, y = 11,
when x = 204, y = 12,
when x = 221, y = 13,
when x = 238, y = 14,
when x = 255, y = 15,
when x = 272, y = 16,
when x = 289, y = 17,
when x = 306, y = 18,
when x = 323, y = 19,
when x = 340, y = 20,