9514 1404 393
Answer:
see attached
Step-by-step explanation:
The equation can be rewritten to vertex form, so you can tell the vertex is at (2, -5). The leading coefficient of 2 means the points will be twice as far apart vertically than they would be if the leading coefficient were 1. A couple of points are shown in the attached.
y = 2(x^2 -4x) +3
y = 2(x^2 -4x +4) +3 -8 . . . . . . complete the square
y = 2(x -2)^2 -5 . . . . . . . . . . . . finish putting in vertex form
Answer:
y= 2x -3
Step-by-step explanation:
Let's rewrite the given equation into the form of y=mx+c, so that we can find the gradient of the line. In this form, m (coefficient of x) is the gradient.
4x -2y= 3
2y= 4x -3
<em>Divide</em><em> </em><em>by</em><em> </em><em>2</em><em> </em><em>throughout</em><em>:</em>
Thus the gradient is 2.
Parallel lines have the same gradient thus the line would also have a gradient of 2.
Substitute m=2 into the equation:
y= 2x +c
To find the value of c, substitute a pair of coordinates.
When x=2, y=1,
1= 2(2) +c
1= 4 +c
c= 1 -4
c= -3
Thus, the equation of the line is y= 2x -3.