for f(x) = -2(x-4)2+2 - set equation to y = -2(x-4)2+2, solve x-4=0, x = 4
axis of symmetry is x = 4
for g(x) = 5x2-10x+7, set equation to y = 5x2-10x+7, solve the square: 5x2 becomes 5(x-1)2 solve x-1 = 0, x = 1
axis of symmetry is x=1
for H(x) what x value would be the centerline so that the graph symmetry is the same on both sides? looking at the graph the top of the arc is on -2
so axis of symmetry is x = -2
I think NO 1. is C.2/3 and i think NO 2. is C. 2/5
if im wrong correct me but have a blessed day/night
=)
The answer is 2 I think.......
Answer:
Is this advanced math?Brcausee
Step-by-step explanation:
F(1) is saying the value of x is 1
Look at the graph where x is 1 and find the y value of where the line is.
At x = 1, the line is at y = 1 ( there is actually a dot showing you the location.
The answer is 1
