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2 years ago

How many games must be played when 7 players are in the tournament?

Mathematics

1 answer:

AURORKA [14]2 years ago

7 0

I believe the answer is 14

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A painter is placing a ladder to reach the third story window, which is 11 feet above the ground and makes an angle with the gro

grandymaker [24]

Answer:

x = 1.91 ft

Step-by-step explanation:

We use cosine because we are dealing with Adj and Hyp

cos 80 = x/11

x = 11 cos 80

x = 1.91 ft

3 0

3 years ago

Factorize:216a^4b+512ab^4

Snezhnost [94]

Answer:
8ab(27a^3 + 64b^3)

5 0

3 years ago

For every 1 litre of water used to make a medicine, 269ml of sucrose and 47ml of saline solution are used. Express the amount of

leonid [27]

Answer:

1000 : 269 : 47

Step-by-step explanation:

A ratio is a way of comparing the value or amount of one quantity to another.

We are to find the ration of water to sucrose to saline solution, hence, it must remain in that order.

Water : Sucrose : Saline solution

The amount of water is 1 litre (1 * 1000 ml = 1000 ml)

The amount of sucrose is 269 ml

The amount of saline solution is 47 ml

Therefore, the ratio of water to sucrose to saline solution is:

W : S : SS = 1000 : 269 : 47

Since 1000, 269 and 47 have no common factors, that is the simplest form of the ratio.

3 0

2 years ago

Find the equation of the line that is perpendicular to y=1/2x-4 and contains the point (4,5)

boyakko [2]

Hdhhdhzhzhzj on da guys you welcome

8 0

2 years ago

!!Plz urgent help!!

Firdavs [7]

Answer:

890 beads can be fitted in the triangular prism.

Step-by-step explanation:

If we can fill the spherical beads completely in the triangular prism,

Volume of the triangular prism = Volume of the spherical beads

Volume of triangular prism = Area of the triangular base × Height

From the picture attached,

Area of the triangular base = $\frac{1}{2}(\text{Base})(\text{Height})$

= $\frac{1}{2}(AB)(BC)$

By applying Pythagoras theorem in the given triangle,

AC² = AB² + BC²

(13)² = 5² + BC²

169 = 25 + BC²

BC² = 144

BC = 12

Area of the triangular base = $\frac{1}{2}(5)(12)$

= 30 cm²

Height of the triangular prism = 18 cm

Volume of the triangular prism = 30 × 18

= 540 cm³

Volume of one spherical bead = $\frac{4}{3}\pi r^{3}$

= $\frac{4}{3}\pi (0.525)^{3}$

= 0.606 cm³

Let there are 'n' beads in the triangular prism,

Volume of 'n' beads = Volume of the prism

540 = 0.606n

n = 890.90

n ≈ 890

Therefore, 890 beads can be fitted in the triangular prism.

3 0

2 years ago