All categories

3 years ago

Determine the volume of a cube with a side length of 7.5m

Mathematics

1 answer:

satela [25.4K]3 years ago

5 0

Answer:

V≈421.88

Step-by-step explanation:

You might be interested in

kim has 1/2 cup of almonds. she uses 1/8 cup of almonds to make a batch of pancakes. how many bathces of panckes can kim make iw

butalik [34]

4 batches of almonds

7 0

3 years ago

Rakesh Travels 45 km in 54 minutes how much time will he take to travel 70 kilometre

Akimi4 [234]

Answer:

84 minutes

Step-by-step explanation:

45:54

70:x

45/54=70/x

45x=70x54 - cross multiply

x=70x54/45 - divide by 45

x=84

6 0

3 years ago

Match each set of equations with the move that turned the first equation into the second.

polet [3.4K]

A goes to number 4
B goes to number 1
C goes to number 5
D goes to number 2
E goes to number 3

8 0

2 years ago

Read 2 more answers

Find dy/dx by implicit differentiation for ysin(y) = xcos(x)

tatyana61 [14]

Answer:

$\frac{dy}{dx}=\frac{\cos(x)-x\sin(x)}{\sin(y)+y\cos(y)}$

Step-by-step explanation:

So we have:

$y\sin(y)=x\cos(x)$

And we want to find dy/dx.

So, let's take the derivative of both sides with respect to x:

$\frac{d}{dx}[y\sin(y)]=\frac{d}{dx}[x\cos(x)]$

Let's do each side individually.

Left Side:

We have:

$\frac{d}{dx}[y\sin(y)]$

We can use the product rule:

$(uv)'=u'v+uv'$

So, our derivative is:

$=\frac{d}{dx}[y]\sin(y)+y\frac{d}{dx}[\sin(y)]$

We must implicitly differentiate for y. This gives us:

$=\frac{dy}{dx}\sin(y)+y\frac{d}{dx}[\sin(y)]$

For the sin(y), we need to use the chain rule:

$u(v(x))'=u'(v(x))\cdot v'(x)$

Our u(x) is sin(x) and our v(x) is y. So, u'(x) is cos(x) and v'(x) is dy/dx.

So, our derivative is:

$=\frac{dy}{dx}\sin(y)+y(\cos(y)\cdot\frac{dy}{dx}})$

Simplify:

$=\frac{dy}{dx}\sin(y)+y\cos(y)\cdot\frac{dy}{dx}}$

And we are done for the right.

Right Side:

We have:

$\frac{d}{dx}[x\cos(x)]$

This will be significantly easier since it's just x like normal.

Again, let's use the product rule:

$=\frac{d}{dx}[x]\cos(x)+x\frac{d}{dx}[\cos(x)]$

Differentiate:

$=\cos(x)-x\sin(x)$

So, our entire equation is:

$=\frac{dy}{dx}\sin(y)+y\cos(y)\cdot\frac{dy}{dx}}=\cos(x)-x\sin(x)$

To find our derivative, we need to solve for dy/dx. So, let's factor out a dy/dx from the left. This yields:

$\frac{dy}{dx}(\sin(y)+y\cos(y))=\cos(x)-x\sin(x)$

Finally, divide everything by the expression inside the parentheses to obtain our derivative:

$\frac{dy}{dx}=\frac{\cos(x)-x\sin(x)}{\sin(y)+y\cos(y)}$

And we're done!

5 0

3 years ago

Which of the following are factors of 11? A/1 B/11 C/4 D/5 E/0 F/22

7nadin3 [17]

Answer:

B and A

Step-by-step explanation:

8 0

3 years ago

Read 2 more answers

Determine the volume of a cube with a side length of 7.5m​

Determine the volume of a cube with a side length of 7.5m