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Nat2105 [25]
3 years ago
11

There are 24 people using the gym. the ratio of men to women is 2:1. how many men are using the gym

Mathematics
1 answer:
RoseWind [281]3 years ago
8 0
16 men and 8 women are using the gym. You can calculate this mentally.
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Farmer Tom's chickens and sheets are in a jumble. He counts 48 heads and 134 legs, how many sheep does he have?
svetlana [45]
48=x+y
143= 2x+4y
y= sheep
48-y = x
143=2(48-y)+4y
143= 96-2y+4y
143=96+2y
47=2y
y=19
19 sheep
4 0
3 years ago
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Please help me out guys. The photo will show you what to do. 50 points cause I need it done fast
Nonamiya [84]

Answer:

a) starting height: 5.5 ft

b) hang time: 5.562 seconds

c) maximum height: 126.5 ft

d) time to maximum height: 2.75 seconds

Step-by-step explanation:

a) The starting height is the height at t=0.

h(0) = -16·0 +88·0 +5.5

h(0) = 5.5

The starting height is 5.5 feet.

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b) The ball is in the air between t=0 and the non-zero time when h(t) = 0. We can find the latter by solving ...

-16t^2 + 8t +5.5 = 0

t^2 -(11/2)t = 5.5/16 . . . . . subtract 5.5, then divide by -16

t^2 -(11/2)t +(11/4)^2 = (5.5/16) +(11/4)^2 . . . . complete the square

(t -11/4)^2 = 126.5/16 . . . . . . . . . . . . . . . . . . . . call this [eq1] for later use

t -11/4 = √7.90625

t = 2.75 +√7.90625 ≈ 5.562

The ball will be in the air about 5.562 seconds.

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c) If we multiply [eq1] above by -16 and add the constant on the right, we get the vertex form of the height equation:

h(t) = -16(t -11/4) +126.5

The vertex at (2.75, 126.5) tells us ...

The maximum height of the ball is 126.5 feet.

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d) That same vertex point tells us ...

The maximum height will be reached at t = 2.75 seconds.

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If you really need answers fast, a graphing calculator can give them to you in very short order (less than a minute).

6 0
3 years ago
Please help me with this question :)​
just olya [345]

Answer:

3rd option.

Step-by-step explanation:

\frac{2|k|}{5} = 4

move 5 to the other side of the equation.

2|k| = 5(4)

2|k| = 20

move 2 to the other side of the equation.

|k| = \frac{20}{2}

k = 10

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3 years ago
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SOOO CLOSEE TO BEING DONEEEE helppppp
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423 \times 10 {}^{2}

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