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3 years ago

PLEASE HELP WITH MATH!!!!!!! 60 points and brainiest!!!!!

1 answer:

5 0

1. x>-2 distribute the three and get 3x+6>0 subtract the 6 to get 3x>-6 then divide by 2 to get -2.
2.x>6 distribute 8 to get 8x+8 and distribute 7 to get 7x+14. Subtract over the 8 to get 8x>7x+6 then subtract over 7x to get x>6
3.distribute the 9 and the 4 to get 9x-27<4x+40 add over the 27 and get 9x<4x+67 subtract over the 4x to get 5x<67 divide by 5 and get x<67/5
4. distribute the 3 and the 2 to get 3x+3 + 2x+4>0 add together the like terms 3x+2x=5x and 3+4=7 to get 5x+7>0 subtract over the seven to get 5x>-7 and then divide by 5 to get x>-7/5 5. first add over -7 to get -9x/11<2. after that multiply by 11 to get -9x<22 then divide by -9 (MAKE SURE YOU FLIP THE INEQUALITY SIGN WHEN MULTIPLYING OR DIVIDING BY A NEGATIVE LIKE -9 IN THIS CASE) you get x>-22/9 6. Add over the 5 to get 3x<9 divide by 3 and get x<3

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Describe how you could use paper folding to illustrate the fraction 1/9.

V125BC [204]

You can fold it 9 times

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4 years ago

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Find the coordinates of the circumcenter for ∆DEF with coordinates D(1,3) E (8,3) and F(1,-5). Show your work.

luda_lava [24]

Answer: The coordinates of the circumcenter is $(\frac{9}{2}, -1)$ .

Explanation:

The coordinates of triangle DEF are D(1,3) E (8,3) and F(1,-5).

Distance formula,

$d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$

$DE=\sqrt{(8-1)^2+(3-3)^2}=7$

$FE=\sqrt{(1-8)^2+(-5-3)^2}=\sqrt{7^2+8^2}$

$DF=\sqrt{(1-1)^2+(-5-3)^2}=8$

Since triangle follows pythagoras theorem,

$(DF)^2+(DE)^2=(FE)^2$

Therefore the given triangle is a right angle triangle.

Or plot these points on a coordinate plane. From the figure we can say that the triangle DEF is a right angle triangle.

The circumcenter of a right angle triangle is the midpoint of the hypotenuse.

The hypotenuse is EF. The midpoint of EF is,

$Midpoint =(\frac{8+1}{2}, \frac{3-5}{2} )=(\frac{9}{2}, -1)$

Therefore, the coordinates of the circumcenter is $(\frac{9}{2}, -1)$ .

5 0

3 years ago

What is 6/4-9/8 +(6/8 )- 2/6

hodyreva [135]

My guy I have no idea so I would just cheat sorry

Explaination

7 0

4 years ago

In a 45° - 45° - 90° right triangle, the length of the hypotenuse is 15 . What is the length on one of the legs?

STALIN [3.7K]

Since 45 = 45
then the two other sides are equal
(15)^2 = (side)^2 + (side)^2
225 = 2 (side)^2 divide 2 to both sides
112.5 = (side)^2 square root
side = 10.6
this is my answer

8 0

3 years ago

PLEASE HURYY

anygoal [31]

Answer:

Step-by-step explanation:

Use the fact that C + 118 = 180 Subtract 118 from both sides

C + 118 - 118 = 180 - 118

C = 62

C + 57 = B C and A are remote interior angles. They equal the exterior angles that are not supplementary to B.

62 + 57 = B

B = 119

6 0

3 years ago