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ss7ja [257]
3 years ago
11

a rectangular prism has a top area of 20ft square and a height of 5ft. what is the volume of this rectangular prism

Mathematics
1 answer:
krok68 [10]3 years ago
7 0
V = Bh
.. = (20 ft^2)*(5 ft)
.. = 100 ft^3

The volume of this rectangular prism is 100 ft^3.
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6w = 77 - 5w<br> What does w equal
Digiron [165]

Answer:

w=7

Step-by-step explanation:

6w=77-5w

Add 5w to both sides

11w=77

Divide both sides by 11

w=7

5 0
2 years ago
The radius of circle A is r cm. The radius of circle B is twice the radius of circle A. What difference between the circumferenc
avanturin [10]

9514 1404 393

Answer:

  2πr cm

Step-by-step explanation:

The circumference of a circle of radius r is ...

  C = 2πr

For a radius of (r cm), the circumference is ...

  A = 2π(r cm) = 2πr cm

For a radius of (2r cm), the circumference is ...

  B = 2π(2r cm) = 4πr cm

Then the difference between the circumferences is ...

  B -A = (4πr cm) -(2πr cm) = 2πr cm . . . . difference in circumference

3 0
2 years ago
What is -(5x+6)-x=-6-6x
Veronika [31]

Answer: All real numbers are solutions.

Step-by-step explanation:

<u>Let's solve your equation step-by-step.</u>

−(5x+6)−x=−6−6x

<u>Step 1: Simplify both sides of the equation.</u>

−(5x+6)−x=−6−6x

−5x+−6+−x=−6+−6x(Distribute)

(−5x+−x)+(−6)=−6x−6(Combine Like Terms)

−6x+−6=−6x−6

−6x−6=−6x−6

<u>Step 2: Add 6x to both sides.</u>

−6x−6+6x=−6x−6+6x

−6=−6

<u>Step 3: Add 6 to both sides.</u>

−6+6=−6+6

0=0

8 0
3 years ago
Name three collinear points.<br> D<br> В.<br> C С<br> N
dolphi86 [110]

Answer:

BD

AC

SN       (might not be one)

AB

Step-by-step explanation:

5 0
2 years ago
25 Points ! Write a paragraph proof.<br> Given: ∠T and ∠V are right angles.<br> Prove: ∆TUW ∆VWU
vladimir2022 [97]

Answer:

Δ TUW ≅ ΔVWU ⇒ by AAS case

Step-by-step explanation:

* Lets revise the cases of congruent for triangles

- SSS  ⇒ 3 sides in the 1st Δ ≅ 3 sides in the 2nd Δ

- SAS ⇒ 2 sides and including angle in the 1st Δ ≅ 2 sides and  

 including angle in the 2nd Δ  

- ASA ⇒ 2 angles and the side whose joining them in the 1st Δ  

 ≅ 2 angles and the side whose joining them in the 2nd Δ  

- AAS ⇒ 2 angles and one side in the first triangle ≅ 2 angles

 and one side in the 2ndΔ

- HL ⇒ hypotenuse leg of the first right angle triangle ≅ hypotenuse

 leg of the 2nd right angle Δ

* Lets solve the problem

- There are two triangles TUW and VWU

- ∠T and ∠V are right angles

- LINE TW is parallel to line VU

∵ TW // VU and UW is a transversal

∴ m∠VUW = m∠TWU ⇒ alternate angles (Z shape)

- Now we have in the two triangles two pairs of angle equal each

 other and one common side, so we can use the case AAS

- In Δ TUW and ΔVWU

∵ m∠T = m∠V ⇒ given (right angles)

∵ m∠TWU = m∠VUW ⇒ proved

∵ UW = WU ⇒ (common side in the 2 Δ)

∴ Δ TUW ≅ ΔVWU ⇒ by AAS case

7 0
2 years ago
Read 2 more answers
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