Hi it is 7n I hope I was right
A) The signs of the first derivative (g') tell you the graph increases as you go left from x=4 and as you go right from x=-2. Since g(4) < g(-2), one absolute extreme is (4, g(4)) = (4, 1).
The sign of the first derivative changes at x=0, at which point the slope is undefined (the curve is vertical). The curve approaches +∞ at x=0 both from the left and from the right, so the other absolute extreme is (0, +∞).
b) The second derivative (g'') changes sign at x=2, so there is a point of inflection there.
c) There is a vertical asymptote at x=0 and a flat spot at x=2. The curve goes through the points (-2, 5) and (4, 1), is increasing to the left of x=0 and non-increasing to the right of x=0. The curve is concave upward on [-2, 0) and (0, 2) and concave downward on (2, 4]. A possible graph is shown, along with the first and second derivatives.
Step-by-step explanation:
4 + x + 3x = 4 ( 5x ) - 3 ( x ) - 10
4 + x + 3x = 4 + 5x - 3 + x - 10
x + 3x + 5x + x = 4 + 4 - 3 - 10
10x = 21
10x % 10 = 21 % 10
x = 2,1
Answer:
20
Step-by-step explanation:
16-12/4+3(6-2) subtract 6 and 2
16-12/4+3+4 divide 12 and 4
16-3+3+4 subtract 16 and 3
13+3+4 add all 3 numbers
13+7
20