1 qt 1 pt 6 oz - 1pt 12 oz =

Pls anyone help need help

Neko [114]

Answer:

- 2 ≤ n < 8

Step-by-step explanation:

The closed circle at - 2 indicates that n can equal - 2

The open circle at 8 indicates that n cannot equal 8

Otherwise n can be all value between - 2 and 8 including - 2, thus

- 2 ≤ n < 8

3 0

3 years ago

Mrs. Ameldo's class has 5 students with blue eyes, 7 with brown eyes, 4 with hazel eyes, and 4 with green eyes. Two students are

Vitek1552 [10]

Answer:

5/19

Step-by-step explanation:

There's no explanation, it's just common sense ‍♀️

7 0

3 years ago

Which number produces a rational number when multiplied by 0.5?

xxMikexx [17]

If the number begins by being rational, multiplying by 0.5 will not change whether or not it is rational. It will remain rational.

That would include any even number 12 * 0.5 = 6

12 started out as rational, so the answer is rational (6)

Any odd number is also rational

23 * 0.5 = 11.5

23 and 11.5 are both rational.

3.636363636 ... is rational so when multiplied by 0.5 the result will be rational.

1.818181818....

So if we start with something irrational like pi

then pi * 0.5 is not rational.

If you have choices, please list them.

4 0

3 years ago

The two largest lizards in the united states are the gila monster and the chuckwalla. The average gila monster is 0.608 meter lo

Mamont248 [21]

Answer:

Gila Monster is 1.54 times that of Chuckwalla.

Step-by-step explanation:

Given:

Average Length of Gila Monster = 0.608 m

Average Length of Chuckwalla = 0.395 m

We need to find the number of times the Gila monster is as the Chuckwalla.

Solution:

Now we know that;

To find the number of times the Gila monster is as the Chuckwalla we will divide the Average Length of Gila Monster by Average Length of Chuckwalla.

framing in equation form we get;

number of times the Gila monster is as the Chuckwalla = $\frac{0.608}{0.395} = 1.5392$

Rounding to nearest hundredth's we get;

number of times the Gila monster is as the Chuckwalla = 1.54

Hence Gila Monster is 1.54 times that of Chuckwalla.

5 0

3 years ago

The fox population in a certain region has a continuous growth rate of 5% per year. It is estimated that the population in the y

kvasek [131]

Answer:

P(t) = A * (1 + r)^t ;

14,922 ;

Year 2013

Step-by-step explanation:

Given the following :

Continuous growth rate(r) = 5% = 0.05

Population in year 2000 = Initial population (A) = 10,100

Time(t) = period (years since year 2000)

A)

Find a function that models the population,P(t) , after (t) years since year 2000 (i.e. t= 0 for the year 2000).

P(t) = A * (1 + r)^t

Trying out our function for t = year 2000, t =0

P(0) = 10,100 * (1 + 0.05)^0

P(0) = 10,100 * 1.05^0 = 10,100

B.)

Use your function from part (a) to estimate the fox population in the year 2008.

Year 2008, t = 8

P(8) = 10,100 * (1 + 0.05)^8

P(8) = 10,100 * 1. 05^8

P(8) = 10,100 * 1.4774554437890625

= 14922.29

= 14,922

c) Use your function to estimate the year when the fox population will reach over 18,400 foxes. Round t to the nearest whole year, then state the year.

P(t) = A * (1 + r)^t

18400 = 10,100 * (1.05)^t

18400/10100 = 1.05^t

1.8217821 = 1.05^t

1.05^t = 1.8217821

In(1.05^t) = ln(1.8217821)

0.0487901 * t = 0.5998151

t = 0.5998151 / 0.0487901

t = 12.293787

Therefore eit will take 13 years

2000 + 13 = 2013

4 0

3 years ago