If the average of six numbers is 18, there sum may be calculated by multiplying this average with 6 which gives us, 108. Three of these numbers have the average of 15. By the same principle, the sum of these numbers is 45. The sum of the remaining numbers in the set may be obtained by subtracting the sum of the three from the total, 108 - 45 which is equal to 63. Thus, the answer is 63.
The missing factor would be (n+2)... If you wanted to understand it, you simply solve 4n^2+9n+2 which gives you (4n+1)(n+2).
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you will have to have a 99% grade
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