Answer:
167.27 mg.
Step-by-step explanation:
We have been given that the half-life of Radium-226 is 1590 years and a sample contains 400 mg.
We will use half life formula to solve our given problem.
, where N(t)= Final amount after t years, 
= Original amount, t/2= half life in years.
Now let us substitute our given values in half-life formula.
Therefore, the remaining amount of Radium-226 after 2000 years will be 167.27 mg.
Answer:
Divide both sides by 6 :)
Answer,a and b, sorry if they are wrong
Answer:
is there a graph
Step-by-step explanation:
Answer:
they are equal
Step-by-step explanation:
Consider the right triangle ABC with sides a, b, and c as shown in the figure.
Let m(\angle A)=\alpha, and m(\angle B)=\beta.
\alpha +\beta=90^{\circ}, so angles A and B are complementary.
According to the definition of sine, and cosine:
\displaystyle{ \sin \alpha= \frac{opposite\ side}{hypotenuse} =\frac{a}{c} , and
\displaystyle{ \cos \beta= \frac{adjacent\ side}{hypotenuse} =\frac{a}{c}
