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3 years ago

mr. bird leaves for a walk at 7:50 a.m. she allows 25 minutes later what time does she arrive to work

Mathematics

1 answer:

Tatiana [17]3 years ago

5 0

Answer: 8:15

Step-by-step explanation:

If she leaves at 7:50 and arrives to work 25 minutes later, then she will get there at 8:15.

Something easy you could use:

7:50 25

+ 10 -10

____ ___

8:00 15

+ 15 -15

____ ____

8:15 0

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Given the function f(x);

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$\begin{gathered} f(x+h)=-4(x+h)^2+4(x+h)-1 \\ f(x+h)=-4(x^2+2xh+h^2)^{}+4(x+h)-1 \\ f(x+h)=-4x^2-4h^2-8xh^{}+4x+4h-1 \end{gathered}$

So;

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Evaluating the second function;

$\begin{gathered} \frac{f(x+h)-f(x)}{h}=\frac{-4x^2-4h^2-8xh^{}+4x+4h-1-(-4x^2+4x-1)}{h} \\ \frac{f(x+h)-f(x)}{h}=\frac{-4x^2-4h^2-8xh^{}+4x+4h-1+4x^2-4x+1}{h} \\ \frac{f(x+h)-f(x)}{h}=\frac{-4x^2+4x^2-4h^2-8xh^{}+4x-4x+4h-1+1}{h} \\ \frac{f(x+h)-f(x)}{h}=\frac{-4h^2-8xh^{}+4h}{h} \end{gathered}$

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$\begin{gathered} \frac{f(x+h)-f(x)}{h}=\frac{-4h^2-8xh^{}+4h}{h}=-4h-8x+4 \\ \frac{f(x+h)-f(x)}{h}=-4h-8x+4 \end{gathered}$

Therefore, we have;

$undefined$

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1 year ago

mr. bird leaves for a walk at 7:50 a.m. she allows 25 minutes later what time does she arrive to work​

mr. bird leaves for a walk at 7:50 a.m. she allows 25 minutes later what time does she arrive to work