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3 years ago

How to subtract unlike faction

2 answers:

7 0

First, multiply the individual fractions in order to get the same denominators. Then, add the numerators and don't change the denominator.

For example:
1/2-1/4

You have to multiple the first fraction by two so both fractions have a denominator of 4.

2/4-1/4
=1/4

vovangra [49]3 years ago

5 0

Example:
6/20 - 1/5
First, you need to find out what the least common denominator (lcd) is.
The lcd is 20 because 20 x 1=20 and 4 x 5 = 20
So ...
6/20 = 6/20 and 1/5 = 4/20
then you take the new fractions and subtract them
6/20 - 4/20 = 2/20
Lastly, if possible you simplify
2/20 =1/10
Hope this helps! I tried to make it as least confusing as possible.

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Help me pleaseeee asap

sdas [7]

Answer:

5089.4cm³ (rounded to 1 d.p.)

Step-by-step explanation:

Volume of cylinder = $\pi$ × r² × h

Volume of cylinder = $\pi$ × 9² × 20

= 1620 $\pi$

= 5089.4cm³ (rounded to 1 d.p.)

4 0

3 years ago

What is the length of the shadow cast by a 12-foot lamp post when the angle of elevation of the sun is 60º? (to the nearest tent

elena-s [515]

Answer:

6.9 foot.

Step-by-step explanation:

Given: Length of lamp post= 12-foot.

The angle of elevation of the sun is 60°.

∴ The length of Lamp post, which is opposite is 12-foot.

Now, finding the length of shadow cast by foot lamp.

Length of shadow is adjacent.

∴ We know the formula for $Tan\theta$ = $\frac{Opposite}{adjacent}$

Next, putting the value in the formula.

⇒ $Tan 60° = \frac{12}{adjacent}$

Cross multiplying both side and using the value of Tan 60°

∴ Adjacent= $\frac{12}{\sqrt{3} } = 6.92$ ≅ 6.9 (nearest tenth value)

6.9 is the length of shadow cast by a 12-foot lamp post.

3 0

3 years ago

A water storage tank has the shape of a cylinder with diameter 14 ft. It is mounted so that the circular cross-sections are vert

andrezito [222]

Answer:

percentage of the total capacity is 75.6%

Step-by-step explanation:

Hello! To solve this problem we follow the following steps

1. draw the complete scheme of the problem (see attached image)

2. To solve this problem we must find the area of the circular sector using the following equation.(c in the second attached image)

$A=\frac{R^2}{2} (\alpha -sin\alpha )$

$\alpha =2arccos(\frac{d}{R})$

3. observing the attached images we replace the values in the equations and find the area of the circular sector, remember that you must transform the angle to radians

$\alpha =2arccos(\frac{5}{7})=88.83$

$A=\frac{R^2}{2} (\alpha -sin\alpha )\\A=\frac{7^2}{2} (88.83-sen88.83)*\frac{\pi rad}{180} =37.57ft^2$

4.we calculate the area of the total circle (At), then subtract the area of the circular sector (Ac) to find the area occupied by water (Aw)

$At=\frac{\pi }{4} (14ft)^2=153.93ft^2$

Aw=At-Ac=153.93-37.57=116.36ft^2

5.Finally, we calculate the percentage that represents the water in the tank by dividing the area of the water over the total area of the tank

$\frac{116.36}{153.93} *100=75.6$

percentage of the total capacity is 75.6%

3 0

3 years ago

2,550 gallons in 30 days

exis [7]

The answer
is 85 gallons
in a day

3 0

3 years ago

Write an equation of the line that passes through (1,2) and is perpendicular to the line y= 1/3x+4

zvonat [6]

Slope-intercept form: y = mx + b

(m is the slope, b is the y-intercept or the y value when x = 0 --> (0, y) or the point where the line crosses through the y-axis)

For lines to be perpendicular, their slopes have to be the negative reciprocal of each other. (Basically flip the sign +/- and the fraction(switch the numerator and the denominator))

For example:

Slope = 2 or $\frac{2}{1}$

Perpendicular line's slope = $-\frac{1}{2}$ (flip the sign from + to -, and flip the fraction)

Slope = $-\frac{3}{4}$

Perpendicular line's slope = $\frac{4}{3}$ (flip the sign from - to +, and flip the fraction)

y = 1/3x + 4 The slope is 1/3, so the perpendicular line's slope is $-\frac{3}{1}$ or -3.

Now that you know the slope, substitute/plug it into the equation:

y = mx + b

y = -3x + b To find b, plug in the point (1, 2) into the equation, then isolate/get the variable "b" by itself

2= -3(1) + b Add 3 on both sides to get "b" by itself

2 + 3 = -3 + 3 + b

5 = b

y = -3x + 5

5 0

3 years ago