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PIT_PIT [208]
3 years ago
15

What is the point slope form of the line with slope 2/5 that passes through the point (-4,-7) ?

Mathematics
2 answers:
Mashcka [7]3 years ago
8 0
Where slpe=m and a point (x1,y1)
the equaton is
y-y1=m(x-x1)

slope=2/5
point is (-4,-7)
remember x-(-y)=x+y

-4=x1
-7=y1
y-(-7)=2/5(x-(-4))
y+7=2/5(x+4)
none of the options are the answer

A. is pass through point (7,4)
B is pass through point (4,7)
C is pass through point (-4,-4)
D is pass through point (-7,-4)

I would guess you made a typo and you meant to write y+7=2/5(x+4) for C

I would guess C
Korolek [52]3 years ago
4 0
The point slope form of the line is:

D. y+4=2/5(x+7)

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Read 2 more answers
4x-5y=-3
tresset_1 [31]
4x - 5y = -3  ⇒ 1st equation
2x + 3z = 4  ⇒ 2nd equation
3y - z = 8     ⇒ 3rd equation

find the value of z.

3y - z = 8
- z = 8 - 3y
z = (8 - 3y) / -1
z = -8 + 3y

Substitute z with its value in the 2nd equation:
2x + 3z = 4
2x + 3(-8 + 3y) = 4
2x - 24 + 9y = 4
2x + 9y = 4 + 24
2x + 9y = 28

find value of x
2x + 9y = 28
2x = 28 - 9y
x = (28 - 9y)/2
x = 14 - 9y/2

Substitute the value of x in 1st equation
4x - 5y = -3
4(14-9y/2) - 5y = -3
56 - 36y/2 - 5y = -3
- 36y/2 - 5y = -3 - 56
- 36y/2 - 5y = - 59
2(-36y/2 - 5y) = 2(-59)
-36y - 10y = -118
-46y = -118
-46y/-46 = -118/-46
y = 2 26/46
y = 2 13/23  

x = 14 - 9y/2
x = 14 - 9 (2 13/23) /2
x = 14 - 9 (59/23) / 2
x = 14 - 531/23 / 2
x = 14 - 531/23 * 1/2
x = 14 - 531/23*2
x = 14 - 531/46
x = (14*46/46) - 531/46
x = 644/46 - 531/46
x = (644-531)/46
x = 113/46
x = 2 21/46

z = -8 + 3y
z = -8 + 3(2 13/23)
z = -8 + 3(59/23)
z = -8 + 177/23
z = (-8*23/23) + 177/23
z = -184/23 + 177/23
z = (-184 + 177)/23
z = -7/23

x = 2 21/46 ; y = 2 13/23 ; z = -7/23

4x - 5y = -3
4(113/46) - 5(59/23) = -3
452/46 - 295/23 = -3
9.826 - 12.826 = -3
-3 = -3

2x + 3z = 4
2(113/46) + 3(-7/23) = 4
226/46 - 21/23 = 4
4.913 - 0.913 = 4
4 = 4

3y - z = 8
3(59/23) - (-7/23) = 8
177/23 + 7/23 = 8
7.696 + 0.304 = 8
8 = 8 

8 0
2 years ago
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