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2 years ago

急急急偷额亏啊啦啦啦突突破凸透镜片片毛巾杆图案天下无双谱

Chemistry

1 answer:

Ymorist [56]2 years ago

8 0

Answer:

Yung explain

Explanation:

Shu makou du mang sugumani hinam dilomaoan

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Una de las maneras de eliminar el NO en las emisiones de humo es hacerle reaccionar con amoniaco

inna [77]

Answer:

Spanish I dont know spanish.

Explanation:

7 0

3 years ago

How many moles are there in 24.00 g of NaCl

Elis [28]

Answer:

The answer to your question is 0.41 moles

Explanation:

Data

moles of NaCl = ?

mass of NaCl = 24 g

Process

To solve this problem just calculate the molar mass of NaCl, and remember that the molar mass of any substance equals to 1 mol.

1.- Calculate the molar mass

NaCl = 23 + 35.5 = 58.5 g

2.- Use proportions and cross multiplication

58.5 g of NaCl ------------------- 1 mol

24.0 g ------------------- x

x = (24 x 1) / 58.5

x = 0.41 moles

6 0

2 years ago

20 mL of Ba(OH)2 solution with unknown concentration was neutralized by the addition of 43.89 mL of a .1355 M HCl solution. Calc

bezimeni [28]

Answer:

Concentration of the barium ions = $[Ba^{2+}] = 0.4654 M$

Concentration of the chloride ions = $[Cl^{-}]=0.9308 M$

Explanation:

$Moles (n)=Molarity(M)\times Volume (L)$

Moles of hydrogen chloride = n

Volume of hydrogen chloride solution = 43.89 mL = 0.04389 L

Molarity of the hydrogen chloride = 0.1355 M

$n=0.1355 M\times 0.04389 L=0.005947 mol$

$Ba(OH)_2+2HCl\rightarrow BaCl_2+2H_2O$

According to reaction, 2 moles of HCl reacts with 1 mole of barium hydroxide.

Then 0.05947 moles of HCl will react with:

$\frac{1}{2}\times 0.05947 mol=0.029735 mol$ barium hydroxide

Moles of barium hydroxide = 0.029735 mol

$Ba(OH)_2(aq)\rightarrow Ba^{2+}(aq)+2OH^-(aq)$

1 mole of barium hydroxide gives 1 mole of barium ion in an aqueous solution. Then 0.029735 moles of barium hydroxide will give:

$=1\times 0.029735 mol= 0.029735 mol$

Volume of solution after neutralization reaction :

= 20.0 mL + 43.89 mL = 63.89 mL = 0.06389 L

Concentration of the barium ions = $[Ba^{2+}]$

$[Ba^{2+}]=\frac{0.029735 mol}{0.06389 L}=0.4654 M$

$Ba(Cl)_2(aq)\rightarrow Ba^{2+}(aq)+2Cl^-(aq)$

1 mole of barium chloride gives 1 mole of barium ions and 2 moles of chloride ions in an aqueous solution.

Then concentration of chloride ions will be:

$[Cl^-]=2\times [Ba^{2+}]=2\times 0.4654 M=0.9308 M$

8 0

3 years ago

Which statement is correct with respect to gross primary productivity

bezimeni [28]

Gross primary production and net primary production. Gross primary production is the amount of chemical energy as biomass that primary producers create in a given length of time.

8 0

3 years ago

Which of the following is true of mixtures?

SCORPION-xisa [38]

A. a mixture is a combination of two or more substances in which each substance retains its own properties.

4 0

3 years ago

急急急偷额亏啊啦啦啦突突破凸透镜片片毛巾杆图案天下无双谱​

急急急偷额亏啊啦啦啦突突破凸透镜片片毛巾杆图案天下无双谱