Question

Brainliest for whoever can calculate the % yield with correct working out!!!

Answer 1

yield = 56.95 %

Explanation:

We have the following chemical reaction:

4 Na (s) + O₂ (g) → 2 Na₂O (s)

number of moles =  mass / molecular weight

number of moles of Na = 1.72 × 10⁻³ / 23 = 0.0748 × 10⁻³ moles

number of moles of Na₂O = 1.32 × 10⁻³ / 62 = 0.0213 × 10⁻³ moles (practical)

Taking in account the stoichiometry of the chemical reaction, we devise the following reasoning:

if        4 moles of Na produces 2 moles of Na₂O

then   0.0748 × 10⁻³ moles of Na produces X moles of Na₂O

X = (0.0748 × 10⁻³ × 2) / 4 = 0.0374 × 10⁻³ moles of Na₂O (theoretical)

yield = (practical mass / theoretical mass) × 100

yield = (0.0213 × 10⁻³ / 0.0374 × 10⁻³) × 100

yield = 56.95 %

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yield of chemical reactions

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