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slamgirl [31]
4 years ago
12

A sample of gas occupies a volume of 67.5 mL . As it expands, it does 131.0 J of work on its surroundings at a constant pressure

of 783 Torr . What is the final volume of the gas g

Chemistry
1 answer:
baherus [9]4 years ago
4 0

Answer:

The final volume V2=1.3175L

Explanation:

between work ( w), pressure ( P ) and volume ( V ) is the following:

w=−PΔV

where,

ΔV=V2−V1

It was stated that the gas is expanding, then the work is done by the system and it is of a negative value .

Note that work, should be expressed in 1L⋅atm=101.3J

CHECK THE ATTACHMENT FOR DETAILED EXPLATION

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What volume of a 6.67 m nacl solution contains 3.12 mol nacl??
natima [27]

The volume of a 6.67 m nacl solution that contains 3.12 mol nacl is 0.468.

You just need to follow this formula:

C = n / V

So, it will be

V = n / C

<span>    = 3.12 / 6.67 moles / Liter </span>

<span>     = 0.468 L</span>

6 0
3 years ago
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What begins to happen to radioactive uranium as soon as a mineral containing it crystallizes from magma?
Aleonysh [2.5K]
<span>The radioactive uranium decays into its daughter product, lead. It would do this in magma as well, as nuclear decay depends on forces within the atom, not on the phase of the material in which the atom is a part.</span>
5 0
3 years ago
The powder mixture (Cu, Al and Fe) = 10g was oxidized from sufficient chloride acid. 1) What are the possible reactions to the p
Mandarinka [93]

Answer:

1) 2Al + 6HCl ⟶ 2AlCl₃ + 3H₂

    Fe + 2HCl ⟶ FeCl₂ + H₂

2) Cu = 2.5 g; Al = 3.5 g; Fe = 4.0 g  

Explanation:

1) Possible reactions

2Al + 6HCl ⟶ 2AlCl₃ + 3H₂

Fe + 2HCl ⟶ FeCl₂ + H₂

2) Mass of each metal

a) Mass of Cu

The waste was the unreacted copper.

Mass of Cu = 2.5 g

b) Masses of Al and Fe

We have two relations :

Mass of Al + mass of Fe = 10 g - 2.5 g = 7.5 g

H₂ from Al + H₂ from Fe = 6.38 L at NTP

i) Calculate the moles of H₂

NTP is 20 °C and 1 atm.

\begin{array}{rcl}pV & = & n RT\\\text{1 atm} \times \text{6.38 L} & = & n \times 0.08206 \text{ L}\cdot\text{atm}\cdot\text{K}^{-1}\text{mol}^{-1} \times \text{293.15 K}\\6.38 & = & 24.06n \text{ mol}^{-1} \\n & = & \dfrac{6.38}{24.06 \text{ mol}^{-1} }\\\\ & = & \text{0.2652 mol}\\\end{array}

(ii) Solve the relationship

 Let x = mass of Al. Then

7.5 - x = mass of Fe

Moles of Al = x/27

Moles of Fe = (7.5 - x)/56

Moles of H₂ from Al = (3/2) × Moles of Al = (3/2) × (x/27) = x /18

Moles of H₂ from Fe = (1/1) × Moles of Fe = (7.5 - x)/56

∴ x/18 + (7.5 - x)/56 = 0.2652

    56x + 18(7.5 - x) = 267.3

      56x + 135 - 18x = 267.3

                        38x = 132.3

                            x = 3.5 g

Mass of Al = 3.5 g

Mass of Fe = 7.5 g - 3.5 g = 4.0 g

The masses of the metals are Cu = 2.5 g; Al = 3.5 g; Fe = 4.0 g

4 0
4 years ago
1. Given the hypotenuse of a 45°, 45°, 90° triangle is 8, find the length of the legs. Leave your answers in radical form if nee
Alex17521 [72]

Answer:

5.66

Explanation:

sin = opposite/hypotenuse

8 sin = opposite

8 sin 45 = 5.66

5 0
4 years ago
Do atoms or molecules in solids have no motion
Svet_ta [14]

Answer:

Well yes and no

Explanation:

The molecules move, but in place. They are constantly vibrating, rotating and so forth.

Atoms do not move at all

5 0
3 years ago
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