True or False:
2 answers:
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When mixture of NaCl and Al₂(SO₄)₃ is allowed to react with excess NaOH, only Al₂(SO₄)₃ reacts with it and NaCl does not react with NaOH due to presence of common ion (Na⁺). On reaction gelatinous precipitate of aluminium hydroxide [Al(OH)₃] is produced. The balanced chemical reaction is represented as-
Al₂(SO₄)₃ + 6NaOH → 2Al(OH)₃ + 3Na₂SO₄
On this reaction, 0.495 g = 0.495/78 moles =6.346 X 10⁻³ moles of Al(OH)₃.
As per balanced reaction, two moles of Al(OH)₃ is produced from one mole Al₂(SO₄)₃. So, 6.346 X 10⁻³ moles of Al(OH)₃ is produced from (6.346 X 10⁻³)/2 moles=3.173 X 10⁻³ moles of Al₂(SO₄)₃= 3.173 X 10⁻³ X 342 g of Al₂(SO₄)₃=1.085 g of Al₂(SO₄)₃.
So, mass percentage of Al₂(SO₄)₃ is= (amount of Al₂(SO₄)₃/total amount of mixture)X100 = =74.8 %.
Answer:
Kindly check the explanation section.
Explanation:
Based on the description of the reacting -OH group containing Compound, the drawing of the chemical compound is given in the attached picture.
So, without mincing words let's dive straight into the solution to the question.
The reaction between the OH containing compound and PCC is an oxidation reaction.
Looking at the carbon number 1 which the first OH group and CH3 are attached to. Oxidation can not occur here as tertiary alcohol can not be oxidize.
Hence, the second OH will be oxidized into a carbonyl group, C = O. Kindly note that when alcohol oxidizes it turns into an aldehyde.
The equation for the reaction is also given the the attached picture.
