It depends on what level of classes you take, but algebra classes in college do tend to be harder than algebra classes in high school or middle school.
V = (pi)r² h
v = (pi)5² h
v = 25(pi) h
take derivative with respect to h
dv/dh = 25(pi)
(dv/dt)*(dt/dh) = dv/dh
dv/dt is given to be 5 cm³
solved for dv/dh = 25(pi)
5(dt/dh) = 25(pi)
dt/dh = 25(pi)/5
dt/dh = 5(pi)
then the recipricol of dt/dh; we want to find dh/dt = 1/(5(pi))
To be a function each x-value (input) should have only one y-value (output). Here you can see when x=2 it has an output of either 5 or 1. Therefore, the relation is NOT a function.
