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Juli2301 [7.4K]
3 years ago
5

Write the number 1,700,000,000 in scientific notation.

Mathematics
1 answer:
Katyanochek1 [597]3 years ago
6 0
The answer is B
hopefully this helps
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Find the equation of the line perpendicular to y=−2 that passes through the point (4, −2).
lawyer [7]

x = 4

because it is perpendicular, the new equation has to be a vertical since the original was horizontal. We know that it passes through (4,-2) so it has to be x=4

4 0
3 years ago
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1. Mitchell got a job at Owens that pays $38,173 a year thanks to the help of an employment agency. The
Akimi4 [234]

Answer:

38174:54*3*0.40

Step-by-step explanation:

1. calculate how much per week by

38174:54

2. than in 3 weeks

38174:54*3

3. than 40 percent of that

x*0.40

7 0
3 years ago
Select all the answers choices that would NOT be part of the domain of f o g(x) if:
SSSSS [86.1K]

fog(x)

\\ \rm\rightarrowtail \dfrac{(2/x+1)+3}{4/x+1)-1}

\\ \rm\rightarrowtail \dfrac{2+3x+3/x+1}{4-x-1/x+1}

\\ \rm\rightarrowtail \dfrac{3x+5}{3-x}

So

\\ \rm\rightarrowtail 3-x\neq 0

\\ \rm\rightarrowtail x\neq 3

Option h is correct

7 0
2 years ago
A rocket is launched straight up from the ground with an initial velocity of 192 feet per second. The equation for the height of
Ivenika [448]

The equation for the height of the rocket at time t given

h= -16t^2+192t

We have to find the time t, when the rocket reaches 560 feet.

That means we have to find t when h = 560 ft. we will place 560 in the place of h to find t now.

h= -16t^2+192t

560 = -16t^2+192t

In the right side, we can check -16 is the common factor. So we will take out -16 from the rigbht side.

560 = -16(t^2 - 12t)

To get rid of -16 from the right side and move it to left side, we will divide both sides by -16.

560/-16 = -16(t^2-12t)/-16

-35 = t^2 -12t

Now we will move -35 to the righ side by adding 35 to both sides.

-35+35 = t^2-12t+35

0 = t^2 -12t+35

t^2-12t+35 = 0

We will factorize thee left side to find the values of t now. We need to find a pair of factors of 35 that by adding them we will get -12.

The pair of factors of 35 are -5 and -7 and by adding -5-7 we will get -12.

t^2-12t+35 =0

(t-5)(t-7) =0

So by using zero product property we will get

t-5 =0

t-5+5 = 0+5

t=5

Also t-7 =0

t-7+7 = 0+7

t=7

So we have got the rocket reaches at 560ft when t = 5 seconds and also when t = 7 seconds.

Now part b.

When the rocket completes its trajectory and hits the ground then the height or h = 0. So we will place h = 0 there in the equation.

h= -16t^2+192t

0= -16t^2 + 192 t

0 = -16(t^2-12t)

-16(t^2-12t) = 0

We will move -16 to the other side by dividing it to both sides.

-16(t^2-12t)/-16 = 0/-16

t^2-12t = 0

We will take out the common factor t from the left side. By taking out t we will get,

t(t-12) = 0

We will use zero product property now. By using that we will get,

t = 0

ans also t-12 = 0

t-12+12 = 0+12

t = 12

When the rocket completes its trajectory and hits the ground the time t can not be 0. When t =0, the rocket starts the trajectory.

So when the rocket completes its trajectory and hits the ground ,

then t = 12seconds.

So we have got the required answers.

6 0
3 years ago
Given the arithmetic sequence an = 4 − 3(n − 1), what is the domain for n? All integers where n ≥ 1 All integers where n > 1
krok68 [10]

All integers where n ≥ 1.

We have given that the sequence,

a_{n} =4-3(n-1)

We have to find the domain for n.

<h3>What is the meaning of arithmetic sequence?</h3>

Arithmetic sequence is a sequence of numbers such that the difference between the consecutive terms is constant. Difference here means the second minus the first.

That is, a_{n} =a+(n-1)d

where a = first term of sequence.

d =common difference.

n =number of terms which belongs to natural numbers

By  the definition of arithmetic sequence n starts with 1

Remember that,the natural number starts with 1

Now, in given sequence  for nth term

a_{n} =4-3(n-1)

The domain for n is All integers where n ≥ 1.

To learn more about the arithmetic sequence visit:

brainly.com/question/20118982

4 0
2 years ago
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