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Mashutka [201]
3 years ago
7

My dog weighed 60 pounds and lost 25% of his weight.how much did he lose

Mathematics
2 answers:
enyata [817]3 years ago
7 0
He lost 15 pounds      
i think that is the answer

stiv31 [10]3 years ago
3 0
He lost 2.4 pounds.

60/.25= 240
240/100= 2.4
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11 times a number increased by 2 is the same as 6 more than 9 times the number. Find the number.
7nadin3 [17]
11x+2 = 9x+6. Subtract 2 from both sides. 11x = 9x+6. subtract 9x from both sides. 2x = 4, divide both sides by 2. x = 2. Substitute the x with 2 and check to see it it works. The numbers should equal each other.
8 0
3 years ago
Write an expression to describe the sequence below. Use n to represent the position of a term in the sequence, where n = 1 for t
likoan [24]

Hello from MrBillDoesMath!

Answer:

a(n) = -3n  , n>= 1

Discussion:

a(1) = -3

a(2) = -6

a(3) = -9

a(4) = -12

The pattern looks like a(n) = -3n

Thank you,

MrB

6 0
3 years ago
PLZ HELP WILL MARK BRANLIEST (No dum answers or I will delete your question - seriously don't be annoying)
Vsevolod [243]

Answer:

A. tan(2π/3) = -\sqrt{3}

4 0
3 years ago
This famous clock tower has a clock face with a diameter of 23 feet. What is the approximate area of this clock face
pashok25 [27]

Answer:

Therefore the approximate area of this clock face is 415.3 feet².

Step-by-step explanation:

Given:

Clock is of Circular Shape,

Diameter = 23 feet

Radius =r =\dfrac{diameter}{2}=\dfrac{23}{2}=11.5\ feet

To Find :

Area of Clock Face = ?

Solution:

Area of Circle having Radius 'r' is given as,

\textrm{Area of Circle}=\pi r^{2}

Substituting the values we get

\textrm{Area of Clock Face}=3.14\times (11.5)^{2}=415.265=415.3\ feet^{2}

Therefore the approximate area of this clock face is 415.3 feet².

7 0
3 years ago
A swimming pool is to be drained. The pool is shaped like a rectangular prism with length 30 feet, wide 18 ft, and depth 4ft. Su
Gala2k [10]

Answer: it will take 9 hours to empty the pool.

Step-by-step explanation:

The pool is shaped like a rectangular prism with length 30 feet, wide 18 ft, and depth 4ft. It means that when the pool is full, its volume is

30 × 18 × 4 = 2160 ft³

If water is pumped out of the pool at a rate of 216ft3 per hour, then the rate at which the water in the pool is decreasing is in arithmetic progression. The formula for determining the nth term of an arithmetic sequence is expressed as

Tn = a + d(n - 1)

Where

a represents the first term of the sequence(initial amount of water in the pool when completely full).

d represents the common difference(rate at which it is being pumped out)

n represents the number of terms(hours) in the sequence.

From the information given,

a = 2160 degrees

d = - 216 ft3

Tn = 0(the final volume would be zero)

We want to determine the number of terms(hours) for which Tn would be zero. Therefore,

0 = 2160 - 216 (n - 1)

2160 = 216(n - 1) = 216n + 216

216n = 2160 - 216

216n = 1944

n = 1944/216

n = 9

8 0
3 years ago
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