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4 years ago

Help me please with this please!!

Mathematics

2 answers:

Ilia_Sergeevich [38]4 years ago

3 0

8) D
9) D
11) Twenty-five thousandths
13) A
14) Sixty-eight and 4 tenths

Not sure on 10 and 12

prisoha [69]4 years ago

3 0

D is the answer to it

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The owner of a toy store received a shipment of 1,552 party favors. The party favors came in 28 boxes. The same number of party

Svetradugi [14.3K]

let

x = the number of party favors in each of the 27 boxes

y = the number of party favors in the last box

the total number of party favors is 1,552

27x + y = 1,552

since 1552 = 57*27 + 13

if we assume that y<x we conclude that there are 57 party favors in each of the 27 boxes and 13 party favors in the last box.

Thank you for posting your question here at brainly. I hope the answer will help you. Feel free to ask more questions.

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3 years ago

-18-16-14- 12-10-8-6Identify the inequality graphed on the number line.A)X-9<3B)x+9<3x-9 <-3D)x +9<-3

Murljashka [212]

The inequality graph shown is a graph of x < -6

The correct option is option B because it is the only one whose solution give x<-6

x + 9 < 3

x < 3 - 9

x < -6

Therefore the answer is B

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1 year ago

Fa-g=a, solve for the letter a

Varvara68 [4.7K]

Step-by-step explanation:

fa - g = a

fa - a = g

a(f - 1) = g

a = g/(f - 1)

7 0

4 years ago

Read 2 more answers

Find a vector of magnitude 3 in the direction of v=4i-3k

pochemuha

Answer:

$\frac{12i}{5} - \frac{9k}{5}$

Step-by-step explanation:

The magnitude of a vector v = ai + bk is

$|v| = \sqrt{a^{2} + b^{2}$

In this problem, we have that:

Find a vector of magnitude 3 in the direction of v=4i-3k:

The first step is finding the unit vector of v, $v_{u}$ .

$|v| = \sqrt{4^{2} + (-3)^{2}} = 5$

$v_{u} = \frac{4i}{5} - \frac{3k}{5}$

Magnitude 3, same direction.

We multiply the unit vector by +3, since it is in the same direction. If it was in the opposite direction, we would have multiplied by -3.

The answer is:

$\frac{12i}{5} - \frac{9k}{5}$

5 0

3 years ago

If the sixth term in a geometric sequence is 1/625, and the common ratio is 15, find the explicit formula of the sequence.

Nonamiya [84]

Answer:

The explicit formula of the sequence is $a_n=5(\frac{1}{5})^{n-1}$ for $n \geq 2$

Step-by-step explanation:

Sixth term in a geometric sequence = $\frac{1}{625}$

Common ratio = $\frac{1}{5}$

Formula of nth term = $a_n=ar^{n-1}$

Substitute the values

So, $\frac{1}{625}=a(\frac{1}{5})^{6-1}\\\frac{1}{625}=a(\frac{1}{5})^{5}\\\frac{1}{625} \times 5^5=a$

5=a

Substitute the value in 1

So, $a_n=5(\frac{1}{5})^{n-1}$

So, Option C is true

Hence the explicit formula of the sequence is $a_n=5(\frac{1}{5})^{n-1}$ for $n \geq 2$

7 0

4 years ago