Explain The probability of tossing a prime number when you toss the cube with numbers one through six

2 answers:

5 0

Probability is (desired outcomes)/(total possible outcomes)

ok, you must make a choice
1. if you believe that 1 is prime (which I don't) go to AAAAAAAAAAA
2. if you believe that 1 is NOT prime, go to BBBBBBBBBBB

AAAAAAAAAAAA
prime numbers from 1 to 6 are
1,2,3,5
desired outcomes=4
total possible =6
4/6=2/3

BBBBBBBBB
prime numbers from 1 to 6 are
2,3,5
3 desired outcomes
6 total possible

3/6=1/2

if you belive that 1 is prime, then 2/3 is probability
if you believe that 1 is NOT prime then 1/2 is probability

Leno4ka [110]3 years ago

4 0

Well, let's start with the numbers: Prime: 1,3,5 Composite: 2,4,6 3:3 or 1/2 or 50%

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Which expression represents rational numbers? Select all that apply

Vladimir79 [104]

Answer:

1. $\sqrt{100} \sqrt{100}$

2. 13.5 + $\sqrt{81}$

3. $\sqrt{9} + \sqrt{729}$

6. $\frac{3}{5} + 2.5\\\frac{3+12.5}{5}\\\frac{15.5}{5}\\= 3.1$

These four options are rational;

Step-by-step explanation:

1. $\sqrt{100} \sqrt{100}$ equals to 10 * 10 = 100 which is rational

2. 13.5 + $\sqrt{81}$ equals 13.5 + 9 = 22.5

3. $\sqrt{9} + \sqrt{729}$ -- 3+27 = 30

6. $\frac{3}{5} + 2.5\\\frac{3+12.5}{5}\\\frac{15.5}{5}\\= 3.1$

Option 4 and 5 are irrational because they include $\sqrt{353}$ and $\sqrt{216}$ which are not a perfect square and their answers will be non recurring and non terminating decimal fraction.