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andre [41]
3 years ago
13

Show that sum of any two medians of a triangle is greater than the third median.

Mathematics
1 answer:
charle [14.2K]3 years ago
4 0
<span><em><u>consider the length of the medians as "a" </u></em>
<em><u>so a+a=2a </u></em>
<em><u>third median =a </u></em>
<em><u>since 2a is greater than a </u></em>
<em><u>sum of two medians of a triangle is greater than the third</u></em></span>
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Find two consecutive integers such that one fifth of the first less one-ninth of the second is 3. Pls answer.​
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Answer:

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Step-by-step explanation:

To solve this problem, we must interpret it line by line;

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   let the first number = x

               second number  = x + 1

  • one - fifth of first;

             \frac{1}{5}x

  •   one - ninth of the second;

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for the "less" ;

         \frac{1}{5}x -  \frac{1}{9}(x + 1) = 3

Multiply through by 45

       45(\frac{1}{5}x) - (45) \frac{1}{9}(x + 1) = 3 x 45

           9x - 5(x + 1) = 135

           9x - 5x -5 = 135

             4x = 135 + 5

              4x = 140

                x = 35

Now, x+1  = 35 + 1 = 36

The consecutive integers are 35 and 36

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