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andre [41]
3 years ago
13

Show that sum of any two medians of a triangle is greater than the third median.

Mathematics
1 answer:
charle [14.2K]3 years ago
4 0
<span><em><u>consider the length of the medians as "a" </u></em>
<em><u>so a+a=2a </u></em>
<em><u>third median =a </u></em>
<em><u>since 2a is greater than a </u></em>
<em><u>sum of two medians of a triangle is greater than the third</u></em></span>
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Tracy had a bag of candies, and none of the candies could be broken into pieces. She ate $\frac{1}{3}$ of them and then gave $\f
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Answer:

72

Step-by-step explanation:

Let the number of candies = n

Tracy ate = 1/3 of n = n/3 remaining 2n / 3

she gave 1/4 of the remainder to her friend = 1/4 of ( n - n/3) = 2n / 12

the new remainder = (2n / 3) - (2n / 12) = n /2

she and her mom then ate altogether = 30

and the brother took from 1 to five, the number he took = x

and she has 3 left

( n/2) - 30 - x = 3

n = 2 ( 33 + x)

now we know that the candies could not be broken  and x is between 1 to 5

n = 2 (33 + 1), 2 (33+2), 2(33 +3), 2 (33+ 4) and 2 (33 + 5) this are the possible values of n, ( 68, 70, 72, 74, 76) and the multiple of 3 is 72

n therefore = 72

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3 years ago
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Step-by-step explanation:

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2 years ago
What are the slope and the y-intercept of the linear function that is represented by the equation y=-10x+1?
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2 years ago
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Given f(x) and g(x) = f(x) + k, look at the graph below and determine the value of k.
Anton [14]

Answer:

Given the graph f(x) = \frac{1}{3}x -2 and g(x) = \frac{1}{3}x + 3

We have to find the value of k;

Since, g(x) = f(x) +k

\frac{1}{3}x+3 = \frac{1}{3}x-2 +k

Subtract \frac{1}{3}x from both sides we get;

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Simplify:

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or

k = 5

Therefore, the value of k = 5


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2 years ago
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