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sdas [7]
3 years ago
13

For the rational equation, x^2+5x+6/x+3=3 , what is a valid value of x?.

Mathematics
2 answers:
gladu [14]3 years ago
8 0
The answer for this question is 1
Anvisha [2.4K]3 years ago
5 0

Answer:

x= -3 and x = 1 are the values.

Step-by-step explanation:

For the rational equation given we have to find the value of x.

\frac{x^{2}+5x+6}{(x+3)}=3

By cross multiplication

x^{2}+5x+6=3(x+3)

We factorize left hand side (L.H.S.) of the equation first.

x^{2}+5x+6=x^{2}+3x+2x+6

         = x(x+3)+2(x+3)

         = (x+2)(x+3)

Now factorized form of the eqation is

(x+2)(x+3)=3(x+3)

(x+2)(x+3)-3(x+3)=0

(x+3)(x-1)=0

x+3= 0 ⇒ x = -3

x - 1 = 0 ⇒  x = 1

Therefore, x= -3 and x = 1 are the values.

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another thing to notice
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5 0
3 years ago
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EastWind [94]

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3 years ago
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egoroff_w [7]

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Answer with explanation:

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