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katen-ka-za [31]
2 years ago
6

Sketch the graph of this linear equation4y = -7x + 1​

Mathematics
1 answer:
jonny [76]2 years ago
6 0

Answer:

use desmos to graph it

.....

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HELP PLEASE if I don’t turn this in it’ll make my grade drop to a 60% I will give brainiest to whoever answers this!
GenaCL600 [577]
2) Larger triangle is twice as large as the smaller one so x is 16
3) 16/12.8= 1.25 (This is the scale factor)
for y: 10/1.25=8
for x: 30/1.25=16
4) 8/6.4=1.25 (Scale factor)
for y: 14/1.25=11.2
for x: 15/1.25= 12
5) 22.5/9= 2.5 (scale factor)
for x: 12x2.5=30
for y: 35/2.5= 14
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7 0
2 years ago
A moose population is growing exponentially following the pattern in the table shown below. Assuming that the pattern continues,
Alika [10]

The population of the moose after 12 years is 7692

Step-by-step explanation:

The form of the exponential growth function is y=a(b)^{x} , where

  • a is the initial value
  • b is the growth factor

The table:

→  x  :  y

→  0  :  40

→  1   :  62

→  2  :  96

→  3  :  149

→  4  :  231

To find the value of a , b in the equation use the data in the table

∵ At x = 0 , y = 40

- Substitute them in the form of the equation above

∵ 40=a(b)^{0}

- Remember any number to the power of zero is 1 (except 0)

∴ 40 = a(1)

∴ a = 40

- Substitute the value of a in the equation

∴ y=40(b)^{x}

∵ At x = 1 , y = 62

- Substitute them in the form of the equation above

∵ 62=40(b)^{1}

∴ 62 = 40 b

- Divide both sides by 40

∴ 1.55 ≅ b

∴ The growth factor is about 1.55

- Substitute its value in the equation

∴ The equation of the population is y=40(1.55)^{x}

To find the population of moose after 12 years substitute x by 12 in the equation

∵ y=40(1.55)^{12}

∴ y ≅ 7692

The population of the moose after 12 years is 7692

Learn more:

You can learn more about the logarithmic functions in brainly.com/question/11921476

#LearnwithBrainly

7 0
2 years ago
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