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2 years ago

11

816 floats were in the parade that lasted 4 hours. Every time 6 floats passed by city hall, the parade stopped. How many times

did the parade stop?

1 answer:

JulsSmile [24]2 years ago

5 0

The parade stopped 136 times you simply divide the number of floats by 6 to find the answer.

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Answer:

$-0.36 a^{5}b^{6} x^{6}$

Step-by-step explanation:

Given:

$a^2x^5b,,\ -0.6axb^2,\ and\ 0.6a^2b^3$

Required

Multiply

The above can be written as

$a^2x^5b * -0.6axb^2\ * \ 0.6a^2b^3$

Split the above expression

$a^2*x^5*b * -0.6*a*x*b^2\ * \ 0.6*a^2*b^3$

Collect like terms

$-0.6 * 0.6 * a^2*a*a^2*b *b^2 *b^3*x^5*x$

Apply first law on indices

$-0.36 * a^{2+1+2} *b^{1+2+3} *x^{5+1}$

$-0.36 * a^{5} *b^{6} *x^{6}$

$-0.36 a^{5}b^{6} x^{6}$

Hence, $a^2x^5b * -0.6axb^2\ * \ 0.6a^2b^3$ is equivalent to $-0.36 a^{5}b^{6} x^{6}$

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