Answer:
5069.04 seconds
Explanation:
The parameter we are looking for is called the Orbital period of the Hubble Space Telescope.
It is given as:
where r = radius of orbit of Hubble Space Telescope
G = gravitational constant = 
M = Mass of earth
We are given that:
r = radius of the earth + distance of HST from earth
r = 
M = 
Therefore, T will be:
The orbital period of the Hubble Space Telescope is 5069.04 seconds.
Answer:
Explanation:
Apparent frequency that is received to the speeder is given as
here we know that
now we have
now the frequency that is received back from the speeder is given as
So difference is the frequency is given as
The answer is zero.
A simple harmonic motion has zero total mechanical energy as it moves beyond the equilibrium point, when it achieves the maximum displacement, when it moves past the equilibrium point, and when it moves past the equilibrium point and a non-zero constant.
What is simple harmonic motion?
- Simple Harmonic Motion (SHM) is a periodic, to and fro shifting rotation about the mean position of the body. The restoring force on an oscillating body is geared toward its mean direction since it is exactly proportional to its displacement.
- The sum of the potential energy and the kinetic energy constitutes the total energy in brainly.com/question/17315536.
- The particle's total mechanical energy when performing simple harmonic motion.
- The sum of the kinetic energy of the block plus the potential energy stored in the spring, which is proportional to the square of the amplitude, makes up the total energy of the block and spring system.
To learn more about simple harmonic motion visit: brainly.com/question/25380728?
#SPJ4
The resultant force is 5N.So the box moves to right with constant acceleration.
