Hooke's law states that for a helical spring the extension is directly proportional to the force applied provided the elastic limit is not exceeded.
Therefore; F= ke, where k is the spring constant, F is the force and e is the extension.
k = 2700 N/m and e = 3 cm or 0.03 M
therefore, F = 2700 × 0.03
= 81 N
Thus, the force required will be 81 N
Answer:.
F = 3.0576sinθ
For any value of θ < 180
Explanation:
Generally, F = BILsinθ
Where,. F = magnetic force magnitude. B = magnetic Field magnitude.
L = length of wire. I = current
Therefore,
B = 0.260 T, L = 2.80 m
I = 4.20 A
: F = 0.260 × 4.20 × 2.80sinθ
∴ F = 3.0576sinθ
157.5J
KE=1/2 mv^2
KE= 1/2(35kg)(3m/s)^2
KE=(17.5kg)(9m^2/s^2)
KE= 157.5J
Answer:
Explanation:
given,
angular speed, ω = 3.90 x 10¹² rad/s
bond length, L = 1.10 Å
molar mass = 28.0 g/mole
Rotational Kinetic energy
now,
moment of inertia ,
......(1)
mass of O₂ = m
mass of O = M = m/2
now, mass
form equation(1)
I = 9.66 x 10⁻⁴⁷ kg.m²
putting value in Rotational kinetic energy equation
Hence, rotational kinetic energy of the molecule is equal to
