1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
ss7ja [257]
3 years ago
12

What two things are needed to create an emission nebula? A) interstellar gas and dust B) hydrogen fusion and helium ionization C

) cool stars and much interstellar dust D) hot stars and interstellar gas, particularly hydrogen E) hydrogen gas and carbon dust
Physics
1 answer:
wolverine [178]3 years ago
8 0

Answer:

D) hot stars and interstellar gas, particularly hydrogen

Explanation:

Emission nebula is the nebula which is formed of the ionized gases which emit light of different wavelengths. The common source of ionization of the emission nebula is high-energy photons mostly which are emitted from hot star present nearby to it.

<u>The emission nebulae include H II regions. An H II region is the region of the interstellar atomic hydrogen which is ionized. It is the cloud of the partially ionized gas in which star formation takes place.</u>

You might be interested in
By the nucleus, protons and neutrons of an atom does it contain more mass
Temka [501]

Answer:

Virtually all the mass of an atom resides in its nucleus, according to Chemistry

Explanation:

7 0
3 years ago
Placing the north pole of a magnet near the south pole of another magnet results in:
MakcuM [25]

Answer:

An attractive force between the magnets. A is the correct answer if it was the north pole facing another north pole magnet the answer would have been a repulsive force between the magnets because the north pole of a magnet does not attract instead it separates from each other which is a repulsive force the best answer is A.

Explanation:

the southern pole of a magnet is a positive force while the northern pole of a magnet is negative .

Note: Magnet can attract each other only when they are facing the opposite directions a north pole will attract a south pole; the magnets pull on each other. But the two north poles will push each other away.

8 0
3 years ago
-<br> ZOOLS<br> 6) The mass of a motorcycle is 250 kg. What is?<br> A) Its weight on Earth in Newtons?<br> B) Its weight on the
marishachu [46]

Answer:

Explanation:

Weight is actually a force. A force can change depending on its location. A mass remains constant no matter where it is.

A)

F = m * a

m = 250 kg

a = 9.81 m/s^2

F = 250 * 9.81 = 2452.5 N

B)

The acceleration due to gravity on the moon is roughly 1/6 what it is on earth. You can check its value in your notes.

a = 9.81 + (1/6) = 1.635

m = 250

F = 250 * 1.635

F = 408.75

C)

The mass is the same anywhere in the universe.

250 kg

4 0
3 years ago
For copper, ρ = 8.93 g/cm3 and M = 63.5 g/mol. Assuming one free electron per copper atom, what is the drift velocity of electro
viktelen [127]

Answer:

V_d = 1.75 × 10⁻⁴ m/s

Explanation:

Given:

Density of copper, ρ = 8.93 g/cm³

mass, M = 63.5 g/mol

Radius of wire = 0.625 mm

Current, I = 3A

Area of the wire, A = \frac{\pi d^2}{4} = A = \frac{\pi 0.625^2}{4}

Now,

The current density, J is given as

J=\frac{I}{A}=\frac{3}{ \frac{\pi 0.625^2}{4}}= 2444619.925 A/mm²

now, the electron density, n = \frac{\rho}{M}N_A

where,

N_A=Avogadro's Number

n = \frac{8.93}{63.5}(6.2\times 10^{23})=8.719\times 10^{28}\ electrons/m^3

Now,

the drift velocity, V_d

V_d=\frac{J}{ne}

where,

e = charge on electron = 1.6 × 10⁻¹⁹ C

thus,

V_d=\frac{2444619.925}{8.719\times 10^{28}\times (1.6\times 10^{-19})e} = 1.75 × 10⁻⁴ m/s

4 0
3 years ago
Read 2 more answers
The mass of the Moon is 7.35 x 1022 kg, while that of Earth is 5.98 x 1024 kg. The average distance from the center of the Moon
Kryger [21]

Answer:

aaa

Explanation:

m_e = Mass of the Earth =  5.98 × 10²⁴ kg

G = Gravitational constant = 6.67 × 10⁻¹¹ m³/kgs²

r_1 = Distance from the center of the Moon to the center of Earth = 6371000 m

r_2 = Distance from the center of the earth center to sun center

m_m = Mass of moon = 7.35\times 10^{22}\ kg

M = Mass of sun = 1.989\times 10^{30}\ kg

F_1=G\frac{m_em_m}{r_1^2}\\\Rightarrow F_1=6.67\times 10^{-11}\frac{5.98\times 10^{24}\times 7.35\times 10^{22}}{(384000000)^2}\\\Rightarrow F_1=1.988\times 10^{20}\ N

F_2=G\frac{Mm_e}{r_1^2}\\\Rightarrow F_2=6.67\times 10^{-11}\frac{5.98\times 10^{24}\times 1.989\times 10^{30}}{(149.6\times 10^9+6371000+695.51\times 10^6)^2}\\\Rightarrow F_2=3.511\times 10^{22} N

\frac{F_1}{F_2}=\frac{1.988\times 10^{20}}{3.511\times 10^{22}}\\\Rightarrow \frac{F_1}{F_2}=0.00566\\\Rightarrow F_1=F_20.00566

Hence the force of moon on earth is 0.00566 times the force of earth on moon center to center

4 0
4 years ago
Other questions:
  • What did Thomson's and Rutherford's experiments have in common?
    5·2 answers
  • A researcher is analyzing data from a high-energy particle collision. the result of the analysis gives a value of 8.8 x 10-19 c
    15·1 answer
  • SOMEONE PLEASE HELP!
    11·1 answer
  • Which of the following would best model the Doppler effect?
    6·1 answer
  • Air conditioners are rated by their coefficient of performance at 61 ∘ F inside temperature and 99 ∘ F outside temperature. An e
    15·1 answer
  • Three equal charges of magnitude 'e' are located at the vertices of an equilateral triangle of side 1m. Where should you place a
    8·1 answer
  • A 24-volt source is required to furnish 48 watts to a parallel circuit consisting of four resistors of equal value. What is the
    8·1 answer
  • A 67.5-kg person throws a 0.0410-kg snowball forward with a ground speed of 34.0 m/s. A second person, with a mass of 57.5 kg, c
    11·1 answer
  • 1. Two boxes stacked on top of one another weigh 100 kg total. They apply
    5·1 answer
  • What is motion ??????​
    6·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!