What two things are needed to create an emission nebula? A) interstellar gas and dust B) hydrogen fusion and helium ionization C
1 answer:
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To solve the problem, we must use the following equation:
where
Q is the amount of heat energy absorbed by the water
m is the mass of the water
Ti and Tf are the initial and final temperature
Cs is the specific heat capacity of the water
The data we have in this problem are:
Q=40.0 kJ
m=0.500 kg
Substituting the data into the equation and re-arranging it, we find
So the final temperature of the water will be 29.1 degrees.
We got the following:
m = 78kg
h = 6m
g = 9.8 m/
≈ 10 m/
----------------------------------------------------------------------------
A = ?
As we know A = Ep = mgh -> potential energy
so the answer would be A = 78 * 6 * 10 = 4680 Joule
m = 78kg
h = 6m
g = 9.8 m/
----------------------------------------------------------------------------
A = ?
As we know A = Ep = mgh -> potential energy
so the answer would be A = 78 * 6 * 10 = 4680 Joule