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Dimas [21]
3 years ago
14

A 5 N force pushes on the right side of a box. At the same time, a 10 N force pushes on the left side of the box. What happens t

o the box?
Physics
2 answers:
notka56 [123]3 years ago
8 0
The resultant force is 5N.So the box moves to right with constant acceleration.
Mrac [35]3 years ago
8 0

Answer: The box will displace towards right side.

Explanation:

In the given problem, a 5 N force pushes on the right side of a box. At the same time, a 10 N force pushes on the left side of the box. The net force acting on the force is 5 N.

The magnitude of the force acting on the box from the left side is more than the force acting on the box from the right side. The body will displace in that direction in which the magnitude of the applied force is more.

The box is displaced to right by a net force of 5 N.

Therefore, the box will displace towards right side.

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Answer:    the answer is d

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3 years ago
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4 0
2 years ago
A 20 kg crate initially at rest on a horizontal floor requires a 80 N horizontal force to set it in motion. Find the coefficient
e-lub [12.9K]

Answer:

<em>The coefficient of static friction between the crate and the floor is 0.41</em>

Explanation:

<u>Friction Force</u>

When an object is moving and encounters friction in the air or rough surfaces, it loses acceleration and velocity because the friction force opposes motion.

The friction force when an object is moving on a horizontal surface is calculated by:

Fr=\mu N          [1]

Where \mu is the coefficient of static or kinetics friction and N is the normal force.

If no forces other then the weight and the normal are acting upon the y-direction, then the weight and the normal are equal in magnitude:

N = W = m.g

The crate of m=20 Kg has a weight of:

W = 20*9.8

W = 196 N

The normal force is also N=196 N

We can find the coefficient of static friction by solving [1] for \mu:

\displaystyle \mu=\frac{Fr}{N}

The friction force is equal to the minimum force required to start moving the object on the floor, thus Fr=80 N and:

\displaystyle \mu=\frac{80}{196}

\mu=0.41

The coefficient of static friction between the crate and the floor is 0.41

7 0
2 years ago
What is a element that tends to be shiny, easy shaped, and a good conductor of heat?
ozzi
The answer to your question is Metal
8 0
3 years ago
A 2500 kg car traveling to the north is slowed down uniformly from an initial velocity of 20 m/s by a 5620 N braking force actin
Dennis_Churaev [7]

Answer:

the distance traveled by the car is 42.98 m.

Explanation:

Given;

mass of the car, m = 2500 kg

initial velocity of the car, u = 20 m/s

the braking force applied to the car, f = 5620 N

time of motion of the car, t = 2.5 s

The decelaration of the car is calculated as follows;

-F = ma

a = -F/m

a = -5620 / 2500

a = -2.248 m/s²

The distance traveled by the car is calculated as follows;

s = ut + ¹/₂at²

s = (20 x 2.5) + 0.5(-2.248)(2.5²)

s = 50 - 7.025

s = 42.98 m

Therefore, the distance traveled by the car is 42.98 m.

5 0
2 years ago
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