How to find density - PLS BE SIMPLE

Chemistry

2 answers:

dimaraw [331]3 years ago

8 0

Mass divided by volume

lianna [129]3 years ago

4 0

Question: How to find density.

Final Answer:

To find the density of any object. Look for the Volume and mass. Once you have the volume and mass of the object. Divide the mass by the volume to get density.

Formula: Mass / Volume = Density.

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At constant temperature and pressure, increasing the amount of a gas will __________.

aivan3 [116]

At constant temperature and pressure, increasing the amount of gas will increase the volume.

6 0

3 years ago

What is a possible quantum number set for an electron in the 3s orbital of a magnesium atom

Alik [6]

n = 3
l = 0
$m_l$ = 0

$m_s$ = 1/2 or -1/2

<h3>Explanation</h3>

There are four quantum numbers in an electron that orbits the atom.

n, the principal quantum number.
l, the angular quantum number.
$m_l$ , the magnetic quantum number.
$m_s$ , the spin quantum number.

n is a positive integer. The value of n indicates the main shell of the electron. The electron in question is in the 3s orbital. As a result, n = 3.

l is a non-negative integer. The value of l indicates the type of subshell ("orbital") of the electron. The types of subshells possible depends on the main shell. For example, both s and p orbitals exist in the second main shell. However, only the s orbital exists in the first main shell. The value of l ranges from 0 to n - 1.

l = 0 indicates an s orbital.
l = 1 indicates a p orbital.
l = 2 indicates a d orbital.
l = 3 indicates an f orbital.

The electron in question is in an s orbital. As a result, l = 0.

$m_l$ is an integer. The value of $m_l$ indicates the position of the electron within the subshell. The range of $m_l$ depends on the value of l. $m_l$ ranges from -l to l (that's -l, ..., -1, 0, 1, ... l). Accordingly, there are 2 l + 1 orbitals in a l subshell. l = 0 for this 3s electron. There's only one orbital in the 3s subshell. The only $m_l$ value possible for this electron is 0.

The value of $m_s$ is either - 1/2 or 1/2. It indicates the position of an electron within a single orbital. The value of $m_s$ does not depend on that of n, l, or $m_l$ . However, by the Pauli Exclusion Principle, at least one of the four numbers must differ for two electrons in the same atom. In case all three of n, l, and $m_l$ are the same, the two electrons must differ in $m_s$ . However, this question asks only for the number of one single electron. Thus, giving either - 1/2 or 1/2 shall work.

<h3>Reference</h3>

Vitz et. al, "5.8 Quantum Numbers (Electronic)", ChemPRIME (Moore et al.), Chemistry Libretexts. 27 Oct 2017.

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3 years ago

If there is a loss of 5.63 x 10-7kg of mass in a nuclear reaction, how many Joules of energy would be released? Recall that c =

Fudgin [204]

Thank you for posting your question here at brainly.

E = mc^2
where E is the energy in joules, 
m is the mass in kilograms, 
and c is the speed of light. 

E = mc^2 
E = (5.63 x 10^-7 kg)(3 x 10^8 m/s)^2 
E = 5.07 x 10^10 J

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4 years ago

The dipole moment of hf is 1.91d. what is the dipole moment of hf in c⋅m? express your answer in coulomb-meters to three signifi

Drupady [299]

6.37x10^-30 coulomb-meters The unit for dipole moments is the Debye which is 1x10^-21 C*m^2/s divided by the speed of light (299792458 m/s). So the conversion factor is 1x10^-21 C*m^2/s / 299792458 m/s = 3.33564095E-30 C*m And converting 1.91 d to Cm gives 1.91 * 3.33564095E-30 C*m = 6.37x10^-30 coulomb-meters

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What device is used to measure atmospheric pressure

yuradex [85]

A Barometer is used to mesure atmosphereic pressure

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