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Salsk061 [2.6K]
4 years ago
12

Question 4 Unsaved When writing electron configuration the 3d block comes after the 4s block. Question 4 options: True False

Chemistry
1 answer:
zmey [24]4 years ago
6 0

Answer:

True

Explanation:

According to Aufbau's principle "sublevels with lower energies are filled up before those with higher energies".

Sublevels do not fill up in numerical order but there is a certain manner in which they are filled. The pattern is shown below:

  1s 2s 2p 3s 3p 4s 3d 4p 5s 4d 5p e.t.c

 We see that the 4s gets filled before the 3d sublevel.

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Which is the best way to determine if an object is made of pure gold?
netineya [11]

Answer:

Acid?

Explanation:

3 0
4 years ago
Please help How many moles of Pb(NO3)2 are required if 12 moles of Al(NO3)3 are produced
krok68 [10]
Answer is: 18 moles of lead(II)-nitrate.

Balanced chemical reaction: 
3Pb(NO₃)₂ + 2AlCl₃ → 2Al(NO₃)₃ + 3PbCl₂.
n(Al(NO₃)₃) = 12 mol.
From chemical reaction: nAl(NO₃)₃) : n(Pb(NO₃)₂) = 2 : 3.
n(Pb(NO₃)₂) = 3 · 12 mol ÷ 2.
n(Pb(NO₃)₂) = 18 mol; amount of substance.
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3 0
3 years ago
Rings are a characteristic of
Ymorist [56]

Answer:

physical

Explanation:

if it is asking to determine what it is a sign of or how to identify that characteristic it would be a physical.

3 0
3 years ago
Calcium and bromine have formed a bond. Leading up to this, calcium gave up electrons. It was a(n) ____.
Ugo [173]

<u><em>Answer:</em></u>

It was a positive ion.

<u><em>Explanation</em></u>

In CaBr, ionic bond is present. When one of the atom loses electrons and gets positive charges and other atom gains electrons and become negative. As a result of positive and nagative charges , a ionic bond formed.

As in this case, Ca loses electrons and become positive ion while on the other hand bromide gets the electrons and become negative ion.

<em>Note:</em>

Electropositive atoms always loose electrons Like Ca while electronegative atoms always gain elelctrons like Br.

5 0
4 years ago
Read 2 more answers
A chemist prepares a solution of iron(II) bromide (FeBr2) by measuring out 46. g of iron(II) bromide into a 400. mL volumetric f
schepotkina [342]

Solution

Given mass of FeBr2 = 85.5 g

Molar mass of FeBr2 = 215.65

No. of Moles of FeBr2 = Given Mass / Molar mass = 85.5 / 215.65

No. of Moles = 0.3964

Given Volume is 450 mL i.e. 0.450 L

Now Concentration = 0.3964/0.450

Hence Concentration = 0.881 mol/L

4 0
3 years ago
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