How does temperature, pressure and surface area affect the dissolving process

2 answers:

8 0

If I am correct, yes. As I was told in chemistry, the surface area affects the dissolving of the "sugar". If you put regular Surat in a hot cup of coffee, it will dissolve at a quick pace, but what if you put the same amount of sugar in the same amour of coffee, but the sugar was fine powder? It would dissolve even faster since it has more surface area. So temperature does affect the dissolving. Hope this helps!

Zarrin [17]3 years ago

8 0

Temperature : - DIssolving process is fastened by increase in temperture.( directly proportional)

Pressure : - Dissolving process is fastened by decrease in pressure.( inversely proportional)

Surface area - Dissolving process is fastened by increase in surface area. ( directly proportional)

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Read 2 more answers

The powder mixture (Cu, Al and Fe) = 10g was oxidized from sufficient chloride acid. 1) What are the possible reactions to the p

Mandarinka [93]

Answer:

1) 2Al + 6HCl ⟶ 2AlCl₃ + 3H₂

Fe + 2HCl ⟶ FeCl₂ + H₂

2) Cu = 2.5 g; Al = 3.5 g; Fe = 4.0 g

Explanation:

1) Possible reactions

2Al + 6HCl ⟶ 2AlCl₃ + 3H₂

Fe + 2HCl ⟶ FeCl₂ + H₂

2) Mass of each metal

a) Mass of Cu

The waste was the unreacted copper.

Mass of Cu = 2.5 g

b) Masses of Al and Fe

We have two relations :

Mass of Al + mass of Fe = 10 g - 2.5 g = 7.5 g

H₂ from Al + H₂ from Fe = 6.38 L at NTP

i) Calculate the moles of H₂

NTP is 20 °C and 1 atm.

$\begin{array}{rcl}pV & = & n RT\\\text{1 atm} \times \text{6.38 L} & = & n \times 0.08206 \text{ L}\cdot\text{atm}\cdot\text{K}^{-1}\text{mol}^{-1} \times \text{293.15 K}\\6.38 & = & 24.06n \text{ mol}^{-1} \\n & = & \dfrac{6.38}{24.06 \text{ mol}^{-1} }\\\\ & = & \text{0.2652 mol}\\\end{array}$