<h3><u><em>Option B</em></u></h3><h3><u><em>The equation of a line, in point- slope form, that passes through (5, -3) and has a slope of 2/3</em></u></h3><h3><u><em /></u>
<u><em /></u></h3>
<em><u>Solution:</u></em>
<em><u>The equation of line in point slope form is given as:</u></em>
Where, "m" is the slope of line
Given that,
slope = 2/3
The line passes through (5, -3)
Substitute m = 2/3 and 
= (5, -3) in point slope form
Thus equation of line in point slope form is found
Answer:
Step-by-step explanation:
Amplitude is twice the coefficent of the sine function. In this case, 
Period is 
divided by the coefficent of x, in this case, 
Phase shift, is how much you sum or subctract from x inside the sine, in this case 
.
Midline you get by hiding the sine and reading what's left, in this case, -4.
Answer:
its (-1/2,-5/2),(2,5)
Step-by-step explanation:
Substitute 2x2−3 for y into y=3x−1then solve for x.
Answer:
7 hours
Step-by-step explanation:
First you subtract 20 from 69, as the starting fee. That leaves you with 49. 49/7 = 7 hours
