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miskamm [114]
3 years ago
5

Solve for x. Please help. Thank you.

Mathematics
2 answers:
REY [17]3 years ago
6 0

16)

The products of the external segment and the entire secant must be equal for both secants.

5(5+x) = 6(6+4)

25 + 5x = 60

5x = 35

x = 7

b)

4(4+x) = 3(3+5)

16 + 4x = 24

4x = 8

x = 2

Good luck!

svet-max [94.6K]3 years ago
4 0
A. outside times the whole, so 6 times 10 = 60. 5 times the whole has to equal 60, so 5 times 12. X=7
b. 3 times 8 = 24. 4 times 6 = 24, which would make x=2 even though that doesn’t look right with the picture. Good luck!
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andrew-mc [135]

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Find the solution of the system of equations<br> shown on the graph.
o-na [289]

Answer:

Answer:(0,3)Step-by-step explanation:The solution in a set of graphs is where they intersect. In this graph, they intersect at (0,3)

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2 years ago
In ΔRST, t = 4.1 inches, r = 7.1 inches and ∠S=45°. Find the length of s, to the nearest 10th of an inch.
dem82 [27]

Answer:

The length of s is 5.1 inches to the nearest tenth of an inch

Step-by-step explanation:

In Δ RST

∵ t is the opposite side to ∠T

∵ r is the opposite side to ∠R

∵ s is the opposite side to ∠S

→ To find s let us use the cosine rule

∴ s² = t² + r² - 2 × t × r × cos∠S

∵ t = 4.1 inches, r = 7.1 inches, and m∠S = 45°

→ Substitute them in the rule above

∴ s² = (4.1)² + (7.1)² - 2 × 4.1 × 7.1 × cos(45°)

∴ s² = 16.81 + 50.41 - 41.1677568

∴ s² = 26.0522432

→ Take √ for both sides

∴ s = 5.10413981

→ Round it to the nearest tenth

∴ s = 5.1 inches

∴ The length of s is 5.1 inches to the nearest tenth of an inch

3 0
3 years ago
Read 2 more answers
Flying with the wind, a small plane flew 404 mi in 2 h. Flying against the wind, the plane could fly only 386 mi in the same amo
Alika [10]

Answer: rate of the plane is 197.5 mph

rate of wind is 4.5 mph

Step-by-step explanation:

Let x represent the rate of the plane in calm air.

Let y represent the rate of the wind.

Flying with the wind, a small plane flew 404 mi in 2 h. This means that the total speed with which the plane flew is (x + y) mph.

Distance = speed × time

Distance travelled by the plane while flying with the wind is

404 = 2(x + y)

Dividing both sides of the equation by 2, it becomes

202 = x + y- - - - - - - - - - - 1

Flying against the wind, the plane could fly only 386 mi in the same amount of time. This means that the total speed at which the plane flew is (x - y) mph.

Distance = speed × time

Distance travelled by the plane while flying against the wind is

386 = 2(x - y)

Dividing both sides of the equation by 2, it becomes

193 = x - y- - - - - - - - - - - 2

Adding equation 1 to equation 2, it becomes

395 = 2x

x = 395/2

x = 197.5

Substituting x = 197.5 into equation 1, it becomes

202 = 197.5 + y

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y = 4.5

3 0
3 years ago
Find the volume of the cubes or rectangular prisms in cubic centimeters.
DanielleElmas [232]

a) Volume of Rectangular prism is \frac{36}{125}\,\,cm^3

b) Volume of cube is \frac{8}{125}\,\,cm^3

c) Volume of cube is \frac{1}{125}\,\,cm^3

d) Volume of Rectangular prism is \frac{6}{125}\,\,cm^3

Step-by-step explanation:

Part a)

Volume of rectangular prism with

length= \frac{3}{5}\,\,cm

width= \frac{4}{5}\,\,cm

height = \frac{3}{5}\,\,cm

The formula used to find Volume of rectangular prism is:

Volume\,\,of\,\,rectangular\,\,prism=length*width*height

Putting values:

Volume\,\,of\,\,rectangular\,\,prism=\frac{3}{5} *\frac{4}{5} *\frac{3}{5}\\Volume\,\,of\,\,rectangular\,\,prism=\frac{36}{125}\,\,cm^3

So, Volume of Rectangular prism is \frac{36}{125}\,\,cm^3

Part b)

Volume of cube with side length of \frac{2}{5}\,\,cm

The formula used to find Volume of cube is:

Volume\,\,of\,\,cube=length^3

Putting value of length and finding volume:

Volume\,\,of\,\,cube=length^3\\Volume\,\,of\,\,cube=(\frac{2}{5})^3\\ Volume\,\,of\,\,cube=\frac{8}{125}\,\,cm^3

So, Volume of cube is \frac{8}{125}\,\,cm^3

Part c)

Volume of cube with side length of \frac{1}{5}\,\,cm

The formula used to find Volume of cube is:

Volume\,\,of\,\,cube=length^3

Putting value of length and finding volume:

Volume\,\,of\,\,cube=length^3\\Volume\,\,of\,\,cube=(\frac{1}{5})^3\\ Volume\,\,of\,\,cube=\frac{1}{125}\,\,cm^3

So, Volume of cube is \frac{1}{125}\,\,cm^3

Part d)

Volume of rectangular prism with

length= \frac{1}{5}\,\,cm

width= \frac{2}{5}\,\,cm

height = \frac{3}{5}\,\,cm

The formula used to find Volume of rectangular prism is:

Volume\,\,of\,\,rectangular\,\,prism=length*width*height

Putting values:

Volume\,\,of\,\,rectangular\,\,prism=\frac{1}{5} *\frac{2}{5} *\frac{3}{5}\\Volume\,\,of\,\,rectangular\,\,prism=\frac{6}{125}\,\,cm^3

So, Volume of Rectangular prism is \frac{6}{125}\,\,cm^3

Keywords: Volume

Learn more about Volume at:

  • brainly.com/question/6443737
  • brainly.com/question/12497249
  • brainly.com/question/12613605

#learnwithBrainly

6 0
3 years ago
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