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3 years ago

24 times what equals 72

Mathematics

2 answers:

zubka84 [21]3 years ago

6 0

24 times 3 equals 72

Alecsey [184]3 years ago

4 0

To do this you could simply divide 72 by 24 and you get 3.

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What is the unit rate of $420 for 15 tickets!

gayaneshka [121]

I could be wrong but I got 28. I devided 420 by 15

3 0

2 years ago

Read 2 more answers

Calculating area of rectangle

PSYCHO15rus [73]

Answer:

$Area = 216.108cm^2$ --- You

$Area = 216.940cm^2$ --- Another student

Reason: Because there is a variation in the given dimensions

Step-by-step explanation:

Given

Your measurement

$Length = 20.70cm; Width =10.44cm$

Another students'

$Length = 20.74cm; Width =10.46cm$

Solving (a): The area

Area is calculated as:

$Area = Length * Width$

For you

$Area = 20.70cm * 10.44cm$

$Area = 216.108cm^2$

For the other student

$Area = 20.74cm * 10.46cm$

$Area = 216.940cm^2$

Solving (b): Reason for the variation in the areas

The given measurements are estimates of the dimensions of the rectangle.

Since there is a variation in the estimates, there will be some level of variation in the calculated area.

4 0

3 years ago

A circular swimming pool has a radius of 28ft. There is a path all the way around the pool that's 4ft wide. A fence is going to

Natalka [10]

Answer:

Therefore 200.96 ft.of fencing are needed to go around the pool path.

Step-by-step explanation:

Given, a circular swimming pool has a radius of 28ft. There is a path all the way around the pool. The width of the path 4 ft.

The radius of the outside edge the pool path is

= Radius of the pool + The width of the path

= (28+4) ft

= 32 ft.

To find the length of fencing, we need to find the circumference of outside the pool path.

Here r= 32 ft

The circumference of outside edge of the pool path

= $2\pi r$

$=(2\times 3.14 \times 32) ft$

=200.96 ft.

Therefore 200.96 ft.of fencing are needed to go around the pool path.

3 0

3 years ago

PLEASE SHOW WORK....

Irina18 [472]

Answer:

Step-by-step explanation:

omg its says you cant have help

8 0

2 years ago

Use implicit differentiation to find the points where the parabola defined by x2−2xy+y2+4x−8y+20=0 has horizontal and vertical t

Komok [63]

Answer:

The parabola has a horizontal tangent line at the point (2,4)

The parabola has a vertical tangent line at the point (1,5)

Step-by-step explanation:

Ir order to perform the implicit differentiation, you have to differentiate with respect to x. Then, you have to use the conditions for horizontal and vertical tangent lines.

-To obtain horizontal tangent lines, the condition is:

$\frac{dy}{dx}=0$ (The slope is zero)

--To obtain vertical tangent lines, the condition is:

$\frac{dy}{dx}=\frac{1}{0}$ (The slope is undefined, therefore the denominator is set to zero)

Derivating respect to x:

$\frac{d(x^{2}-2xy+y^{2}+4x-8y+20)}{dx} = \frac{d(x^{2})}{dx}-2\frac{d(xy)}{dx}+\frac{d(y^{2})}{dx}+4\frac{dx}{dx}-8\frac{dy}{dx}+\frac{d(20)}{dx}$ = $2x -2(y+x\frac{dy}{dx})+2y\frac{dy}{dx}+4-8\frac{dy}{dx}= 0$