Answer:
Step-by-step explanation:
This equation looks complicated.We have to make it easier
let's say x^2/3 = t and x^4/3 = t^2
t^2-10t+21=0 [ we can factorize this equation as a (t-3)(t-7) ]
(t-3)(t-7)=0 [ that means , t can be 3 or 7 ]
But don't forget we have to find x not t so,
t=x^2/3=3 ∛ x^2 = 3 x^2 = 9 x=3 or x= -3
t=x^2/3=7 ∛x^2 = 7 x^2 = 343 x ~18.5 or x ~ -18.5
Answer:
x=-2.25,y=-2.25
Step-by-step explanation:
The given system is

We want to solve the system for x and y that makes the system true.
Let us multiply the first equation by 3 while maintaining the second equation:

Subtract the current second equation from the first one.

Divide through by 12:

From the second equation we have:

This implies that:

Answer:
<h2>

</h2>
solution,

Combine the like terms:

Simplify:

Hope this helps...
Good luck on your assignment...
C = 2 (pi) r
32 (pi) = c
32 (pi)= 2 (pi) r
r= 16
2r = d
d= 32
hope that helps