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Sphinxa [80]
3 years ago
5

Desmond knows that 2 cakes will feed 11 people. If he is inviting 58 people to his parents' anniversary party, how many cakes wi

ll he need?
5 cakes
6 cakes
10 cakes
11 cakes
​
Mathematics
1 answer:
Sauron [17]3 years ago
4 0
11 cakes; 2/11=x/58, cross multiply, 11x=(2)(58), 11x=116, x=116/11=10.54, you would need 11 cakes.
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Given the quadratic function f(x) = 4x^2 - 4x + 3, determine all possible solutions for f(x) = 0
solong [7]

Answer:

The solutions to the quadratic function are:

x=i\sqrt{\frac{1}{2}}+\frac{1}{2},\:x=-i\sqrt{\frac{1}{2}}+\frac{1}{2}

Step-by-step explanation:

Given the function

f\left(x\right)\:=\:4x^2\:-\:4x\:+\:3

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0=4x^2-4x+3

switch both sides

4x^2-4x+3=0

subtract 3 from both sides

4x^2-4x+3-3=0-3

simplify

4x^2-4x=-3

Divide both sides by 4

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Add (-1/2)² to both sides

x^2-x+\left(-\frac{1}{2}\right)^2=-\frac{3}{4}+\left(-\frac{1}{2}\right)^2

x^2-x+\left(-\frac{1}{2}\right)^2=-\frac{1}{2}

\left(x-\frac{1}{2}\right)^2=-\frac{1}{2}

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solving

x-\frac{1}{2}=\sqrt{-\frac{1}{2}}

x-\frac{1}{2}=\sqrt{-1}\sqrt{\frac{1}{2}}                 ∵ \sqrt{-\frac{1}{2}}=\sqrt{-1}\sqrt{\frac{1}{2}}

as

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so

x-\frac{1}{2}=i\sqrt{\frac{1}{2}}

Add 1/2 to both sides

x-\frac{1}{2}+\frac{1}{2}=i\sqrt{\frac{1}{2}}+\frac{1}{2}

x=i\sqrt{\frac{1}{2}}+\frac{1}{2}

also solving

x-\frac{1}{2}=-\sqrt{-\frac{1}{2}}

x-\frac{1}{2}=-i\sqrt{\frac{1}{2}}

Add 1/2 to both sides

x-\frac{1}{2}+\frac{1}{2}=-i\sqrt{\frac{1}{2}}+\frac{1}{2}

x=-i\sqrt{\frac{1}{2}}+\frac{1}{2}

Therefore, the solutions to the quadratic function are:

x=i\sqrt{\frac{1}{2}}+\frac{1}{2},\:x=-i\sqrt{\frac{1}{2}}+\frac{1}{2}

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