Ask question

Ask question

All categories

4 years ago

5

Desmond knows that 2 cakes will feed 11 people. If he is inviting 58 people to his parents' anniversary party, how many cakes wi

ll he need?
5 cakes
6 cakes
10 cakes
11 cakes

1 answer:

Sauron [17]4 years ago

4 0

11 cakes; 2/11=x/58, cross multiply, 11x=(2)(58), 11x=116, x=116/11=10.54, you would need 11 cakes.

You might be interested in

Rewrite the following equation in slope-intercept form. 17x + 15y = 5 Write your answer using integers, proper fractions, and im

omeli [17]

Answer:
y = $\frac{-17}{15} x$ + $\frac{1}{3}$

Explanation:
The slope-intercept form of the equation has the following formula:
y = mx + c
where:
m is the slope
c is the y-intercept

The given is:
17x + 15y = 5

To put it in the slope-intercept formula, we should isolate the y as follows:
17x + 15y = 5
15y = -17x + 5
y = (-17/15) x + (5/15)
y = $\frac{-17}{15} x$ + $\frac{1}{3}$
where:
m is the slope = -17/15
c is the y-intercept = 1/3

Hope this helps :)

7 0

3 years ago

PLEASE HELP 13 INSTEAD OF FIVE POINTS!!!! I REALLY NEED HELP

devlian [24]

A is what the answer is

6 0

3 years ago

Read 2 more answers

6<br> x<br> −<br> 5<br> y<br> =<br> 14<br><br> Find <br> x<br> when <br> y<br> =<br> 2

sattari [20]

Answer:

4

Step-by-step explanation:

3 0

3 years ago

Batteries produced by a manufacturing company have had a life expectancy of 135 hours. Because of an improved production process

Nikolay [14]

Answer: c. z = 1.35; Reject the null hypothesis

Step-by-step explanation:

Let $\mu$ be the average life expectancy of its batteries.

As per given , we have

Null hypothesis : $H_0 : \mu =135$

Alternative hypothesis : $H_a : \mu >135$

Since $H_a$ is right-tailed and population standard deviation is also known, so we perform right-tailed z-test.

Test statistic : $\dfrac{\overlien{x}-\mu}{\dfrac{\sigma}{\sqrt{n}}}$

where, n= sample size

$\overlien{x}$ = sample mean

$\mu$ = Population mean

$\sigma$ =population standard deviation

For $n=42,\ \overline{x}=140\ \&\ \sigma=24$ , we have

$z=\dfrac{140-135}{\dfrac{24}{\sqrt{42}}}=1.35015431217\approx1.35$

Critical one-tailed test value for 0.10 significance level :

$z_{0.1}=1.28$

Decision : Since critical z value (1.28) < test statistic (1.35), so we reject the null hypothesis .

[When critical value is less than the test statistic value , we reject the null hypothesis .]

5 0

3 years ago

What is the value of 5-8×(7-15+8)

salantis [7]

Answer:

I'm pretty sure that the answer is 5. Correct me if i'm wrong

Step-by-step explanation:

6 0

3 years ago