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3 years ago

What is the diameter of a hemisphere with a volume of 257 m^3

Mathematics

1 answer:

Alex73 [517]3 years ago

4 0

Answer:

9.9

Step-by-step explanation:

\text{Volume of Hemisphere}\text{:}

Volume of Hemisphere:

\,\,257

257

\text{Volume of Sphere}\text{:}

Volume of Sphere:

\,\,514

514

Double volume of hemisphere to get volume of the entire sphere

\text{Volume of a Sphere:}

Volume of a Sphere:

V=\frac{4}{3}\pi r^3

πr

514=

\,\,\left(\frac{4}{3}\pi\right) r^3

(

π)r

514=

\,\,(4.1887902)r^3

(4.1887902)r

Evaluate 4/3pi in calc

\frac{514}{4.1887902}=

4.1887902

514

\,\,\frac{(4.1887902)r^3}{4.1887902}

4.1887902

(4.1887902)r

Evaluate \frac{4}{3}\pi

π in calc

122.7084611=

\,\,r^3

\sqrt[3]{122.7084611}=

122.7084611

\,\,\sqrt[3]{r^3}

Cube root both sides

4.9692575=

\,\,r

\text{Then the diameter equals }9.938515

Then the diameter equals 9.938515

diameter is radius times 2

\text{Final Answer:}

Final Answer:

d\approx 9.9\text{ m}

d≈9.9 m

Round to nearest tenth

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Two investments totallng $47,500 produce an annual income of $3000. One investment ylelds 9% per year, while the other yields 6%

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Answer:

The correct answer is "$5000".

Step-by-step explanation:

The given values are:

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Other yield,

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Let,

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2 years ago

Write a polynomial function of minimum degree with real coefficients whose zeros include those listed. Write the polynomial in s

Jobisdone [24]

Answer:

$f(x)=x^4-9x^2-50x-150$

Step-by-step explanation:

Let f(x) be the polynomial function of minimum degree with real coefficients whose zeros are 5, -3, and -1 + 3i be f(x).

By the complex conjugate property of polynomials, -1-3i is also a root of this polynomial.

Therefore the polynomial in factored form is $f(x)=(x-5)(x+3)(x-(-1+3i))(x-(-1+3i))$

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$f(x)=x^4-9x^2-50x-150$

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