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labwork [276]
3 years ago
11

Given Trinagle ABC with A(-4, -2), B(4,4), and C(18,-8), answer the following questions.

Mathematics
1 answer:
True [87]3 years ago
8 0
For the answer to the question above, the slope of segment AC is  (-6/22) = -3/11.

The slopes of perpendicular lines are negative reciprocals, so 
you know that the slope of the perpendicular bisector will be 11/3.

The midpoint of segment AC is  (7, -5).

Now you have the slope of the perpendicular bisector, and a
point on it.  You should be able to complete the equation now.

Notice how sneaky this question is.  You don't need to know
point-B at all, and you don't even need to know that there's
any triangle.  All you need to know is points  A  and  C.
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If P(-4,-2) and Q(1, -3) represent points in a coordinate
Artyom0805 [142]

Answer:

the answer is (6, -4)

Step-by-step explanation:

4 0
3 years ago
You have the set of all the integers from (-16) to 26, inclusive. You take two of the
Vesnalui [34]

The greatest difference you can get is 42

The range of the integer is given as:

Smallest = -16

Largest = 26

So, the range is calculated as:

Range = Largest - Smallest

Substitute known values

Range = 26 - (-16)

Evaluate the difference

Range = 42

Hence, the greatest difference you can get is 42

Read more about range at:

https://brainly.in/question/6887467

6 0
2 years ago
Read 2 more answers
To two decimal places, find the value of k that will make the function f(x) continuous everywhere. f of x equals the quantity 3x
Fiesta28 [93]

Given function is

f(x)=\left\{\begin{matrix}3x+k & x\leq -4 \\ kx^2-5 & x> -4\end{matrix}\right.

now we need to find the value of k such that function f(x) continuous everywhere.

We know that any function f(x) is continuous at point x=a if left hand limit and right hand limits at the point x=a are equal.

So we just need to find both left and right hand limits then set equal to each other to find the value of k

To find the left hand limit (LHD) we plug x=-4 into 3x+k

so LHD= 3(-4)+k

To find the Right hand limit (RHD) we plug x=-4 into

kx^2-5

so RHD= k(-4)^2-5

Now set both equal

k(-4)^2-5=3(-4)+k

16k-5=-12+k

16k-k=-12+5

15k=-7

k=-\frac{7}{15}

k=-0.47

<u>Hence final answer is -0.47.</u>




7 0
3 years ago
Can someone help me with this? Preferably with an explanation on how to actually figure this out. Thank you!
zhannawk [14.2K]

Answer:

2^-4, 1/16, (1/2)^4

There is a rule with exponents, if you are dividing two exponents you subtract the first exponent from the other to simplify it, also meaning it's equivalent.

So in this case 5-9 = 2^-4

The others were found by evaluation.

5 0
3 years ago
What is the final answer for 6x-6-7x=-13/2
olya-2409 [2.1K]
6x - 6 - 7x = -13/2

Multiply both sides by 2:
12x - 12 - 14x = -13

Simplify:
-2x - 12 = -13

Add 12 to both sides:
-2x = -1

Divide both sides by 2:
-x = -1

Change to a positive value of x:
x = 1

6 0
3 years ago
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