The quadratic formula is:
![x=\frac{-b+\sqrt{(b)^2-4(a)(c)}}{2a}](https://tex.z-dn.net/?f=x%3D%5Cfrac%7B-b%2B%5Csqrt%7B%28b%29%5E2-4%28a%29%28c%29%7D%7D%7B2a%7D)
and
![x=\frac{-b-\sqrt{(b)^2-4(a)(c)}}{2a}](https://tex.z-dn.net/?f=x%3D%5Cfrac%7B-b-%5Csqrt%7B%28b%29%5E2-4%28a%29%28c%29%7D%7D%7B2a%7D)
Let's identify our a, b, and c values:
a: -1
b: 1
c: 12
Plug in the values for a, b, and c into the equation. Let's do the first equation:
![x=\frac{-1+\sqrt{(1)^2-4(-1)(12)}}{2(-1)}](https://tex.z-dn.net/?f=x%3D%5Cfrac%7B-1%2B%5Csqrt%7B%281%29%5E2-4%28-1%29%2812%29%7D%7D%7B2%28-1%29%7D)
Simplify everything in the radical:
![x=\frac{-1+\sqrt{49}}{-2}](https://tex.z-dn.net/?f=x%3D%5Cfrac%7B-1%2B%5Csqrt%7B49%7D%7D%7B-2%7D)
Simplify the radical:
![x=\frac{-1+7}{-2}](https://tex.z-dn.net/?f=x%3D%5Cfrac%7B-1%2B7%7D%7B-2%7D)
Combine like terms:
![x=\frac{6}{-2}](https://tex.z-dn.net/?f=x%3D%5Cfrac%7B6%7D%7B-2%7D)
Simplify:
![x=-3](https://tex.z-dn.net/?f=x%3D-3)
This is one solution, now, let's solve for the other equation:
Since when simplified, everything is the same except the subtraction sign, we can skip the simplification again and change the sign to subtraction:
![x=\frac{-1-7}{-2}](https://tex.z-dn.net/?f=x%3D%5Cfrac%7B-1-7%7D%7B-2%7D)
Combine like terms:
![x=\frac{-8}{-2}](https://tex.z-dn.net/?f=x%3D%5Cfrac%7B-8%7D%7B-2%7D)
Simplify:
![x=4](https://tex.z-dn.net/?f=x%3D4)
Your final answers are:
![x=-3](https://tex.z-dn.net/?f=x%3D-3)
![x=4](https://tex.z-dn.net/?f=x%3D4)
ok what do you want me to do for you
Answer:
2
Step-by-step explanation:
x^2=2
Answer:
yes
Step-by-step explanation:
The small triangle is similar to the large triangle (AA),
3/x = x/6
x² = 3 x 6
x² = 18
x = √18
x = √9√2
x = 3√2
The answer is D. The value of x is 3√2 units.