1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Sladkaya [172]
3 years ago
12

NEED HELP!!!

Chemistry
1 answer:
Mekhanik [1.2K]3 years ago
8 0

Answer:

b. The shorter the half-life, the more dangerous the radioisotope.

You might be interested in
He total power used by humans worldwide is approximately 15 TW (terawatts). Sunlight striking Earth provides 1.336 kW per square
SCORPION-xisa [38]

Answer:

id

Explanation:

idk

3 0
3 years ago
Why does a catalyst work for a long time before it needs replacing?
DedPeter [7]
Because the catalyst is not really part of the reaction. it is something that speed up a reaction by lowering the energy need for the reaction to take place. however, in the end the catalyst is brought back to its initial state. that's why it is long lasting
7 0
3 years ago
Draw the molecule by placing atoms on the grid and connecting them with bonds. Include all lone pairs of electrons. Show the for
Alexus [3.1K]

Answer:

See explanation below

Explanation:

In this case, let's see both molecules per separate:

In the case of SeO₂ the central atom would be the Se. The Se has oxidation states of 2+, and 4+. In this molecule it's working with the 4+, while oxygen is working with the 2- state. Now, how do we know that Se is working with that state?, simply, let's do an equation for it. We know that this molecule has a formal charge of 0, so:

Se = x

O = -2

x + (-2)*2 = 0

x - 4 = 0

x = +4.

Therefore, Selenium is working with +4 state, the only way to bond this molecule is with a covalent bond, and in the case of the oxygen will be with double bond. See picture below.

In the case of CO₂ happens something similar. Carbon is working with +4 state, so in order to stabilize the charges, it has to be bonded with double bonds with both oxygens. The picture below shows.

5 0
3 years ago
Which condition must be met in order for an equation to be balanced?
olga55 [171]

Answer:

The elements in the reactants are the same as the elements in the products.

Explanation:

You can't have more or less elements or atoms, but you also can't just have the same number of atoms because then it could be different elements, which can't happen.

5 0
3 years ago
Read 2 more answers
A 0.187 M weak acid solution has a pH of 3.99. Find Ka for the acid. Express your answer using two significant figures.
Anna35 [415]

Answer:

5.56 × 10⁻⁸

Explanation:

Step 1: Given data

  • Concentration of the weak acid (Ca): 0.187 M
  • pH of the solution: 3.99

Step 2: Calculate the concentration of H⁺

We will use the following expression.

pH = -log [H⁺]

[H⁺] = antilog -pH = antilog -3.99 = 1.02 × 10⁻⁴ M

Step 3: Calculate the acid dissociation constant (Ka)

We will use the following expression.

Ka = \frac{[H^{+}]^{2} }{Ca} = \frac{(1.02 \times 10^{-4})^{2} }{0.187} = 5.56 \times 10^{-8}

3 0
3 years ago
Other questions:
  • - If I initially have a gas at a pressure of 379 mmHg, a volume of 467 mL, and a temperature of
    5·1 answer
  • An instrument that allows you to look closely at objects that are invisible to the human eye, including cells
    14·1 answer
  • Please help me with some extra details please
    13·1 answer
  • Why is alchemy not considered a science
    11·1 answer
  • Which of the structure below represents fat
    7·1 answer
  • When light hits the Earth at a greater angle, what does this cause?​
    13·1 answer
  • How important is economic in your everyday life
    14·1 answer
  • A heliox deep-sea diving mixture contains 2.0 gg of oxygen to every 98.0 gg of helium. What is the partial pressure of oxygen wh
    7·1 answer
  • A 3.00 L flexible container holds a sample of hydrogen gas at 153 kPa.
    8·1 answer
  • Dentify the reagents used to carry out the chlorination of benzene. a. cl2/ccl4 b. cl2/fecl3 c. cl2/nacl d. both b and c e. a, b
    11·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!