Answer:
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Responda:
+ 0,9kJ / mol
Explicação:
Dados os calores de combustão do enxofre monoclínico e enxofre rômbico como - 297,2 kJ / mol e - 296,8 kJ / mol, respectivamente para a variação na transformação de 1 mol de enxofre rômbico em enxofre monoclínico conforme mostrado pela equação;
S (mon.) + O2 (g) -> SO2 (g)
Uma vez que são todos 1 mol cada, a mudança na entalpia será expressa como ∆H = ∆H2-∆H1
Dado ∆H2 = -296,8kJ / mol
∆H1 = -297,2kJ / mol
∆H = -296,8 - (- 297,2)
∆H = -296,8 + 297,2
∆H = 297,2-296,8
∆H = + 0,9kJ / mol
Portanto, a mudança na entalpia da equação é + 0,9kJ / mol
Answer:
a) Ag(NH₃)₂⁺, Cl⁻.
b) NH₃.
c) AgCl.
Explanation:
Based on LeChatelier's law, a system in chemistry can change responding to a disturbance of concentration, temperature, etc. in order to restore a new state.
In the reaction:
AgCl(s) + 2NH₃(aq) ⇌ Ag(NH₃)₂⁺(aq) + Cl⁻(aq)
When reactants are added, the system will produce more products restoring the equilibrium and vice versa. A reactant in solid state doesn't take part in the equilibrium, thus:
a) Ag(NH₃)₂⁺, Cl⁻. The addition of products will shift the equilibrium to the left
b) NH₃. The addition of reactant will shift the equilibrium to the right.
c) As AgCl is in solid phase, will not shift the equilibrium in either direction.
The force that caused that was gravity.
The sugar would dissolve better under warmer temperatures because the hot particles interfere with the sugars particles.
