Question

Work the following question out on your own sheet of paper and submit a picture of your work:

Answer 1

Answer:

Heat  absorbed by water = 3985.26 j

Explanation:

Given data:

Mass of water = 75 g

Initial temperature = 20.0°C

Final temperature = 32.7°C

Specific heat of water  = 4.184 j/g.°C

Heat  absorbed by water = ?

Solution:

Specific heat capacity:

It is the amount of heat required to raise the temperature of one gram of substance by one degree.

Formula:

Q = m.c. ΔT

Q = amount of heat absorbed or released

m = mass of given substance

c = specific heat capacity of substance

ΔT = change in temperature

ΔT = 32.7°C - 20°C

ΔT = 12.7 °C

Q = 75 g ×4.184 j/g.°C ×12.7 °C

Q = 3985.26 j