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Ray Of Light [21]
3 years ago
6

Work the following question out on your own sheet of paper and submit a picture of your work:

Chemistry
1 answer:
valina [46]3 years ago
7 0

Answer:

Heat  absorbed by water = 3985.26 j

Explanation:

Given data:

Mass of water = 75 g

Initial temperature = 20.0°C

Final temperature = 32.7°C

Specific heat of water  = 4.184 j/g.°C

Heat  absorbed by water = ?

Solution:

Specific heat capacity:

It is the amount of heat required to raise the temperature of one gram of substance by one degree.

Formula:

Q = m.c. ΔT

Q = amount of heat absorbed or released

m = mass of given substance

c = specific heat capacity of substance

ΔT = change in temperature

ΔT = 32.7°C - 20°C

ΔT = 12.7 °C

Q = 75 g ×4.184 j/g.°C ×12.7 °C

Q = 3985.26 j

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NNADVOKAT [17]

Answer:

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Explanation:

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3 years ago
The substance in acid rain that makes it more acidic than natural rainwater is _____.
sasho [114]
I’m pretty sure it’s sulphur dioxide
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Level 1: 2Sr + 02 > 2Sro
tekilochka [14]

Answer:

Sr would be the limiting reactant

5 moles

Explanation:

Since the equation is a balanced equation, the coefficient shows how each substance relates to the other in terms of the number of moles.

Reactants would be those on the left hand side of the arrow, while the products would be found on te right and side of the arrow. In this question, the reactants would be Sr and O₂.

Limiting reactant is the reactant that is insufficient; meaning to say that there is not enough of that substance and thus the reaction cannot continue. The other reactant(s) that is not limiting is called the excess reactants.

From the balanced equation, 2 moles of Sr is needed to react with 1 mole of O₂. Thus, if we have 5 moles of each reactant, Sr would be the limiting reactant since for every 1 mole of O₂, there has to be 2 moles of Sr in order for the reaction to proceed. Thus, if we have 5 moles of O₂, we would need 10 moles of Sr.

When we work out the amount of products formed, we look at the number of moles of the limiting reactant. This is because the limiting reactant determines how much is being reacted, while the excess number of moles of the excess reactant will remain unreacted.

For every 2 moles of Sr reacted, 2 moles of SrO would be produced. This means that the mole ratio of Sr to SrO is 1:1. Thus, since 5 moles of Sr has been reacted, 5 moles of the product (SrO) would be produced.

8 0
3 years ago
Which solution has the higher boiling point?
dedylja [7]

NaCl has higher boiling point than C₂H₆O₂ in H₂O.

<h3>What is molality?</h3>
  • The number of moles of solute in a solution equal to 1 kg or 1000 g of solvent is referred to as its molality.
  • The definition of molarity, on the other hand, is based on a certain volume of solution.
  • Mol/kg is a typical molality measurement unit in chemistry.
<h3>Calculation of boiling point:</h3>

When the non-volatile solute is dissolved in a solvent, the boiling point rises along with the molality (concentration) of the solute.

Given,

Mass of  C₂H₆O₂ (solute) = 15.0 g

Mass of solvent (H₂O) = 0.50 kg

Molar mass of C₂H₆O₂ = 62 g/mol

Thus, the moles of solute = 15.0 g x 1.0 mol solute/62 g/mol

= 0.2419 mol

Therefore, molality(m) of C₂H₆O₂ (solute) = Amount of solute (mol)/ Mass of solvent

= 0.2419/0.50

= 0.4838 m

Similarly,

Given ,

Mass of  NaCl (solute) = 15 g

Mass of solvent (H₂O) = 0.50 kg

Molar mass of NaCl (solute) = 58.44 g/mol

Thus, the moles of NaCl (solute) = 15.0 g x 1.0 mol solute/58.44

= 0.2566 mol

Therefore, molality(m) of NaCl (solute) = Amount of solute (mol)/ Mass of solvent

= 0.2566 mol/0.50 kg  

= 0.51 m

Hence, the molality of NaCl (solute) is more than the molality of C₂H₆O₂(solute).

So, with an increase in the solute's concentration (molality), the boiling point rises.

Therefore, NaCl has higher boiling point than C₂H₆O₂ in H₂O.

Learn more about boiling point here:

brainly.com/question/24168079

#SPJ4

7 0
2 years ago
Step 2: measure the area of the top of the syringe
Elena L [17]

I am unsure if this is correct, but this might be the whole section:

  • The top of the syringe is a circle. You need to compute its area for use in later computations of pressure values. Start by using a ruler to measure the diameter. Estimate to the nearest 0.01 cm. <em>Answer: </em><em>3.60 </em><em>cm</em>
  • Divide by two to find the radius. Maintain significant figures. <em>Answer: </em><em>1.80 </em><em>cm</em>
  • Substitute the radius into the formula A = πr² to find the area of the top of the syringe. Maintain significant figures. <em>Answer: </em><em>10.2 </em><em>cm²</em>
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3 years ago
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