When dT = Kf * molality * i
= Kf*m*i
and when molality = (no of moles of solute) / Kg of solvent
= 2.5g /250g x 1 mol /85 g x1000g/kg
=0.1176 molal
and Kf for water = - 1.86 and dT = -0.255
by substitution
0.255 = 1.86* 0.1176 * i
∴ i = 1.166
when the degree of dissociation formula is: when n=2 and i = 1.166
a= i-1/n-1 = (1.166-1)/(2-1) = 0.359 by substitution by a and c(molality) in K formula
∴K = Ca^2/(1-a)
= (0.1176 * 0.359)^2 / (1-0.359)
= 2.8x10^-3
Answer:
114.4 grams of P₄O₁₀
Explanation:
P₄ + 5O₂ → P₄O₁₀
50 grams of P₄ are (50 g / 123.88 g/m) = 0.403 moles
Ratio is 1:1 so 0.403 moles of phosphorus can produce the same amount of P₄O₁₀.
Molar mass P₄O₁₀ = 283.88 g/m
0.403 moles . 283.88 g/m = 114.4 g
3420m
Explanation:
Given parameters:
Length of path = 6200m
time taken for the horse to run = 22.5min
speed = 152meters/minute
Unknown:
Distance run by the horse = ?
Solution:
Speed is the rate of change of distance with time.
Speed = 
Distance = speed x time
Distance = 152 x 22.5 = 3420m
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The estimated population of the sea turtles for that location is 160 turtles
Let b represent the total turtles in the location.
<h3>Data obtained from the question</h3>
- Captured marked turtle = 15
The estimated turtles in sea can be obtained as follow:
Mark in sea / Total in sea = captured marked turtle / Captured turtle
40 / b = 15 / 60
Cross multiply
b × 15 = 40 × 60
b × 15 = 2400
Divide both side by 15
b = 2400 / 15
b = 160 turtles
Thus, the estimated turtles in the sea is 160 turtles
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Answer:
Moles = 10.625 mol
Explanation:
Molarity is the amount of solute dissolved per unit volume of solution. It is expressed as,
Molarity = Moles / Volume of Solution ----- (1)
We can also rearrange this equation in terms of moles as,
Moles = Molarity × Volume of Solution ------(2)
Data Given;
Molarity = 4.25 mol.L⁻¹
Volume = 2.50 L
Now, putting value of Molarity and Volume in eq. 2,
Moles = 4.25 mol.L⁻¹ × 2.50 L
Moles = 10.625 mol
