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2 years ago

15

For a new Blueberry muffin recipe, Ms. Morrison used 44 blueberries for 8 muffins. What fraction of blueberries are in each muff

in?

2 answers:

nalin [4]2 years ago

5 0

Answer:

5.5 or 5 1/2

Step-by-step explanation:

She uses 44 blueberries in 8 muffins. So to find the amount of blueberries in each muffin, we divide 44 by 8.

44/8

8 goes into 44 5 times, and there is a remainder of 4. Divide 4 by 8, it is half. so she uses 5.5 blueberries in each muffin

lesya [120]2 years ago

3 0

Answer:

2over11

Step-by-step explanation:

8 over 44

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In an experiment, a ball is drawn from an urn containing 11 orange balls and 8 blue balls. If the ball is orange, three coins ar

Sophie [7]

Answer:

a) 4

b) 12

Step-by-step explanation:

Since, when an orange ball is drawn, three coins are tossed. So, sample points are OHHH, OHHT, OHTH, OHTT. OTHH, 0THT, OTTH, OTTT

So, clearly, 8 sample points will have an orange ball.

When a blue ball is drawn, two coins are tossed. So, sample points are BHH,BHT,BTH,BTT.

So, clearly, 4 samples points will when a blue ball is drawn.

Total samples points=4+8=12

4 0

3 years ago

How to round 106.327 to nearest hundredths explain

scoray [572]

Answer:

106.33

Step-by-step explanation:

after decimal you have .3 tenths 2 hundredths 7 thousandths

to round to the nearest hundredths look at thousandths 7 becasuse is greater then 5 then you round up

106.327 is rounded to 106.33

8 0

2 years ago

Read 2 more answers

Suppose that the length of a side of a cube X is uniformly distributed in the interval 9

Nastasia [14]

Answer:

$f(v) = \left \{ {{\frac{1}{3}v^{-\frac{2}{3}}\ 9^3 \le v \le 10^3} \atop {0, elsewhere}} \right.$

Step-by-step explanation:

Given

$9 < x < 10$ --- interval

Required

The probability density of the volume of the cube

The volume of a cube is:

$v = x^3$

For a uniform distribution, we have:

$x \to U(a,b)$

and

$f(x) = \left \{ {{\frac{1}{b-a}\ a \le x \le b} \atop {0\ elsewhere}} \right.$

$9 < x < 10$ implies that:

$(a,b) = (9,10)$

So, we have:

$f(x) = \left \{ {{\frac{1}{10-9}\ 9 \le x \le 10} \atop {0\ elsewhere}} \right.$

Solve

$f(x) = \left \{ {{\frac{1}{1}\ 9 \le x \le 10} \atop {0\ elsewhere}} \right.$

$f(x) = \left \{ {{1\ 9 \le x \le 10} \atop {0\ elsewhere}} \right.$

Recall that:

$v = x^3$

Make x the subject

$x = v^\frac{1}{3}$

So, the cumulative density is:

$F(x) = P(x < v^\frac{1}{3})$

$f(x) = \left \{ {{1\ 9 \le x \le 10} \atop {0\ elsewhere}} \right.$ becomes

$f(x) = \left \{ {{1\ 9 \le x \le v^\frac{1}{3} - 9} \atop {0\ elsewhere}} \right.$

The CDF is:

$F(x) = \int\limits^{v^\frac{1}{3}}_9 1\ dx$

Integrate

$F(x) = [v]\limits^{v^\frac{1}{3}}_9$

Expand

$F(x) = v^\frac{1}{3} - 9$

The density function of the volume F(v) is:

$F(v) = F'(x)$

Differentiate F(x) to give:

$F(x) = v^\frac{1}{3} - 9$

$F'(x) = \frac{1}{3}v^{\frac{1}{3}-1}$

$F'(x) = \frac{1}{3}v^{-\frac{2}{3}}$

$F(v) = \frac{1}{3}v^{-\frac{2}{3}}$

So:

$f(v) = \left \{ {{\frac{1}{3}v^{-\frac{2}{3}}\ 9^3 \le v \le 10^3} \atop {0, elsewhere}} \right.$

8 0

2 years ago

What is the area of this figure?

coldgirl [10]

Answer: 102

-----------------------------------------------

We'll use the formula
A = h*(b1+b2)/2
where
A = area of trapezoid
h = height
b1 & b2 are the parallel bases

In this case,
b1 = 6+7 = 13
b2 = 21
h = 6

Making the area to be
A = h*(b1+b2)/2
A = 6*(13+21)/2
A = 6*(34)/2
A = 204/2
A = 102

Side Note: We don't use the slanted side of 10 cm at all

3 0

3 years ago

What is the volume of this cone?

olchik [2.2K]

Answer:

The volume of the cone is approximately 453.0 cm³

Step-by-step explanation:

The volume of a cone is one third that of a cylinder with the same height and radius. That gives us 1/3 πr²h, where r is radius and h is height.

However, we are not given the height of the cone, but the side length. We can work out the height using the Pythagorean theorem, as we have a right triangle with the height, base radius, and length. You may recall that the Pythagorean theorem states that the square of the hypotenuse of a right triangle is equal to the sum of the squares of it's other two sides:

$a^2 = b^2 + c^2$

So we can find the height of the cone with that:

$10.8^2 = 7.4^2 + h^2\\h^2 = 10.8^2 - 7.4^2\\h^2 = 116.64 - 54.76\\h^2 = 61.88\\h = \sqrt{61.88}\\h \approx 7.9$

Now that we have the cone's height, we can solve for its volume:

$v = \frac{1}{3} \pi r^2 h\\v = \frac{1}{3} \pi \times 7.4^2 \times 7.9\\v = \frac{1}{3} \pi \times 54.76 \times 7.9\\v = \frac{1}{3} \pi \times 432.6\\v = \pi \times 144.2\\v \approx 453.0 cm^3$

5 0

3 years ago

Read 2 more answers