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Tcecarenko [31]
2 years ago
15

1 + hk + j use h=-5, j = -6, and k = 6 Help me

Mathematics
1 answer:
allsm [11]2 years ago
7 0

9514 1404 393

Answer:

  -35

Step-by-step explanation:

Put the values where the corresponding variables are and do the arithmetic.

  1 + hk + j

  = 1 + (-5)(6) +(-6)

  = 1 -30 -6

  = -35

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\green{\large\underline{\sf{Solution-}}}

<u>Given expression is </u>

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can be rewritten as

\rm \:  =  \: \dfrac{5 \times  { {(5}^{2} )}^{n + 1}  -  {5}^{2}  \times  {5}^{2n} }{5 \times  {5}^{2n + 3}  -  {( {5}^{2} )}^{n + 1} }

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\purple{\rm :\longmapsto\:\boxed{\tt{  {( {x}^{m} )}^{n}  \: = \:   {x}^{mn}}}} \\

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\purple{\rm :\longmapsto\:\boxed{\tt{ \:  \:   {x}^{m} \times  {x}^{n} =  {x}^{m + n} \: }}} \\

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can be further rewritten as

\rm \:  =  \: \dfrac{{5}^{2n + 2 + 1}  - {5}^{2n + 2} }{{5}^{2n + 2 + 2}  -  {5}^{2n + 2} }

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