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4 years ago

A number line shows 1 1/4, -2 2/4, and -1 3/4. Which statement is NOT true?

Mathematics

1 answer:

PIT_PIT [208]4 years ago

7 0

B is not true c is kind of incorrect but atuck with B

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What is equivalent to log9w

Anit [1.1K]

log9+logw is equivalent to log9w.

log9w=log9+logw

8 0

3 years ago

BEST ANSWER the brainliest! This is for my test!

Fantom [35]

Answer:

15.4 m

Step-by-step explanation:

5 0

3 years ago

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A town planner wants to build two new streets, Elm Street and Garden Road, to connect parallel streets Maple Drive and Pine Aven

Advocard [28]

Answer:

72°

Step-by-step explanation:

From the information given:

A town planner wants to build two new streets, Elm Street and Garden Road, to connect parallel streets Maple Drive and Pine Avenue.

We are also told that there is a Trapezoid EFGH with EH as the Pine avenue and EF as the Elm street.

However, side FG and EH are parallel.

∠G = 108°

From the property of parallel lines :

since FG || EH

Then ∠G = ∠H = 108° (i.e corresponding angle will also be equal)

The required angle between Elm Street and Pine Avenue would be interior angles + 180° given that alternate angles are also equal.

The required angle between Elm Street and Pine Avenue = 180° - 108°

The required angle between Elm Street and Pine Avenue = 72°

3 0

3 years ago

Winona’s bowling scores for the past nine weeks are 195, 180, 195, 212, 208, 231, 179, 246, and 195. Find the mean, median, and

belka [17]

Answer: Mean = 204.6 , Median = 195 and mode =195

Step-by-step explanation:

The given data for Winona’s bowling scores for the past nine weeks : 195, 180, 195, 212, 208, 231, 179, 246, 195.

The formula to find Mean is given by :-

$\text{Mean}=\dfrac{\text{Sum of all observations}}{\text{Number of observations}}\\\\=\dfrac{1841}{9}=204.555555556\approx204.6$

For median , first we arrange data values in order as

179, 180, 195, 195, 195, 208, 212, 231, 246

Since the number of data values is 9 (odd).

∴ Median = Middle most data value = 195

Also, Mode = Most occurring data value = 195

3 0

3 years ago

What is the difference of the polynomials? (–2x3y2 + 4x2y3 – 3xy4) – (6x4y – 5x2y3 – y5)

ANEK [815]

For the answer to the question above, I'll provide my solutions to my answers for the problem below.

(–2x3y2 + 4x2y3 – 3xy4) – (6x4y – 5x2y3 – y5)

(−2x3)(y2)+4x2y3+−3xy4+−1(6x4y)+−1(−5x2y3)+−1(−y5)

(−2x3)(y2)+4x2y3+−3xy4+−6x4y+5x2y3+y5

−2x3y2+4x2y3+−3xy4+−6x4y+5x2y3+y5

−2x3y2+4x2y3+−3xy4+−6x4y+5x2y3+y5

(−6x4y)+(−2x3y2)+(4x2y3+5x2y3)+(−3xy4)+(y5)

−6x4y+−2x3y2+9x2y3+−3xy4+y5
So the answer is,
= −6x4y−2x3y2+9x2y3−3xy4+y5

I hope this helps

4 0

4 years ago

Read 2 more answers